Answer:
Number 1: x = 5
Number 2: y = 3, x = 1
Number 3: x = 40
Step-by-step explanation:
For Number 1 you have to keep in mind that quadrilaterals have an interior angle measurement of 360°.
With that in mind, all the angles must add up to 360° (duh).
(20x - 16) + (81) + (16x + 10) + (15x + 30)
20x - 16 + 81 + 16x + 10 + 15x + 30 = 360
That's a bloody mess! We should really combine like terms.
20x <em>- 16 </em>+ <em>81 </em>+ 16x +<em> 10</em> + 15x + <em>30</em>
51x + 105 = 360
That looks a lot better, basic algebra from here, where we droppin' bois?
51x = 255
x = 5
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This one's real easy.
In a parallelogram, the sides opposite from each other are equal, therefore:
2y + 2 = 4y - 4
and
x + 6 = 7x
Both are <em>very </em>easy to solve, here:
2y + 2 = 4y - 4
2y + 6 = 4y
6 = 2y
3 = y
<em>Easy!</em>
x + 6 = 7x
6 = 6x
1 = x
<em>Are you kidding me? This is easy stuff, kid.</em>
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In a Rhombus, in case you didn't know, its diagonals (the lines connecting points diagonal to each other) are ALWAYS perpendicular to one another (intersect at 90°) which means:
2x + 10 = 90
2x = 80
x = 40
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That will be all, ya boi Keith.
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