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3 years ago

Two fractions equivalent to 5/4

Mathematics

2 answers:

Eduardwww [97]3 years ago

6 0

Answer:

10/8, 20/16

Step-by-step explanation:

astraxan [27]3 years ago

5 0

Answer:

1.)10/8

2.)15/12

Step-by-step explanation:

hope this helps

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Whitepunk [10]

The boxes from left to right are

100
2
25/3

The ratio is 5/3 pies to cakes so
Top square = bottom square times 5/3
OR
Bottom square = top square times 3/5

7 0

3 years ago

Read 2 more answers

Please help with these two problems. Show work

MissTica

Answer:

For the first one, it is 1150. For the second one, it is 2460.

Step-by-step explanation:

Think of 23 x 50 as (20 x 50) + (3 x 50).

20 x 50 is 1000. 3 x 50 is 150. 1000 + 150 is 1150.

Think of 30 x 82 as (30 x 80) + (30 x 2)

30 x 80 is 2400. 30 x 2 is 60. 2400+60 is 2460.

3 0

3 years ago

Read 2 more answers

10 points!!

Contact [7]

The slope of the equation would be 7/3 since the original slope was -3/7. We already know y int (b) so the eqn is

y = 7/3x + 2

3 0

3 years ago

At the zoo tje ratio of snakes to lizards is 3:2 A. If there were 10 lizards ,how many snakes would be there be? B.If there were

yawa3891 [41]

Answer:

Part A) $15\ snakes$

Part B) $6\ lizards$

Part C) The zoo would need to get four more lizards to maintain the same proportion

Part D) 12 snakes and 8 lizards

Step-by-step explanation:

Part A) If there were 10 lizards ,how many snakes would be there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

we have that

$y=10\ lizards$

substitute the value of y in the equation A

$\frac{x}{10}=\frac{3}{2}$

solve for x

$x=10(3)/2\\x=15\ snakes$

Part B) If there were 9 snakes ,how many lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

we have that

$x=9\ snakes$

substitute the value of x in the equation A

$\frac{9}{y}=\frac{3}{2}$

solve for y

$y=9(2)/3\\y=6\ lizards$

Part C) If the number of snakes in the zoo is increased by 6, how many more lizards would the zoo need to get to keep the same ratio?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

For $x=6\ snakes$

substitute the value of x in the equation A

$\frac{6}{y}=\frac{3}{2}$

solve for y

$y=6(2)/3\\y=4\ lizards$

therefore

The zoo would need to get four more lizards to maintain the same proportion

Part D) If the total number of snakes and lizards at the zoo was 20, how many snakes and lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$

isolate the variable x

$x=1.5y$ ----> equation A

$x+y=20$ ----> equation B

solve the system by substitution

substitute equation A in equation B

$1.5y+y=20$

solve for y

$2.5y=20$

$y=8\ lizards$

Find the value of x

$x=1.5(8)=12\ snakes$

therefore

12 snakes and 8 lizards

8 0

3 years ago

In a picture, there are 40 monkeys, and 60% of the monkeys are in the trees. How many monkeys are in the trees? Use a 10-squares

frez [133]

Answer:

24 monkeys are in the trees

Step-by-step explanation:

The only part I don´t know how to do is the 10-square model

4 0

2 years ago

Read 2 more answers