Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
 
        
                    
             
        
        
        
Answer:
the answer is x=−1 and y=1
Step-by-step explanation:
hoped I helped:)
 
        
             
        
        
        
Answer:
 one is correct.
Step-by-step explanation:
because it have one solution when you graph it 
 
        
                    
             
        
        
        
Answer:
A reflection on the y axis, then a reflection on the x axis, then a translation of 7 units to the left
Step-by-step explanation:
plz mark me as brainliest
 
        
             
        
        
        
Answer:
Integers
Rational Numbers
Whole Numbers
In their respectful orders.