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swat32
3 years ago
5

Answer this plese I NEED IT NOW OR I WILL FAIL

Mathematics
1 answer:
miv72 [106K]3 years ago
6 0

Answer:

Wait what are we trying to solve here?

Step-by-step explanation:

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Guided Practice
NARA [144]

Answer:

C.

1 ≤ w ≤ 5

Step-by-step explanation:

Move all terms not containing  

w

from the center section of the inequality.

Inequality Form:

1 ≤ w ≤ 5

Interval Notation:

[ 1 , 5 ]

4 0
3 years ago
Rachel earned $89.70 on Tuesday she spent $55.89 at the grocery store how much money does she have left
Artyom0805 [142]
she has 33.81 dollars left
8 0
3 years ago
Read 2 more answers
In response to a gss question in 2006 about the number of hours spent per day watching television, the responses by the fifteen
NemiM [27]

Answer:

Standard error = 0.4

Step-by-step explanation:

Step 1

We find the Standard Deviation

The formula = √(x - mean)/n - 1

n = 15

Mean = 1.93 hours

= √(0- 1.93)² + (0-1.93)² +(0- 1.93)²+( 0- 1.93)²+ (1- 1.93)² + (1- 1.93)² +(1 - 1.93)² +(2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + (2 - 1.93)² + ( 2 - 1.93)² +(4 - 1.93)² +(4 - 1.93)² + (5 - 1.93)²/15 - 1

= √(3.737777776 + 3.737777776 + 3.737777776 + 0.871111111 +0.871111111 + 0.871111111 + 0.004444444445+ 0.004444444445 + 0.004444444445 + 0.004444444445 + 0.004444444445 + 1.137777778 + 4.271111112 + 4.271111112 + 9.404444446)/15 - 1

= √2.352380952

= 1.533747356

Step 2

We find the standard error

The formula = Standard Deviation/√n

Standard deviation = 1.533747356

n = 15

= 1.533747356/√15

= 1.533747356 /3.87298334621

= 0.39601186447

Approximately = 0.4

Therefore, the standard error is 0.4

4 0
3 years ago
Which expression has value of 15 when = 12?
frosja888 [35]

Answer:

I think its 3p not sure but u can try that

3 0
3 years ago
PLEASE HELP ME!!!!!!!!!
vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
1 year ago
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