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swat32
2 years ago
5

Answer this plese I NEED IT NOW OR I WILL FAIL

Mathematics
1 answer:
miv72 [106K]2 years ago
6 0

Answer:

Wait what are we trying to solve here?

Step-by-step explanation:

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Suppose Cesar Chavez lead a March with 6,300 people. If the ratio of marchers who were not farmworkers to farmworkers is 4:5, ho
baherus [9]

Answer:

3500.

Step-by-step explanation:

We have been given that Cesar Chavez lead a March with 6,300 people. The ratio of marchers who were not farm-workers to farm-workers is 4:5. We are asked to find the number of marchers, who were farm-workers.

First of all, we will find the ratio of farm-workers to total marchers as:

\frac{\text{Farm-workers}}{\text{Total marchers}}=\frac{\text{Farm-workers}}{\text{Farm-workers+non-farm-workers}}=\frac{5}{4+5}=\frac{5}{9}

To find the number of marchers, who were farm-workers, we need to find \frac{5}{9} of whole marchers.

\text{Number of marchers that were farm-workers}=6300\times \frac{5}{9}

\text{Number of marchers that were farm-workers}=700\times \frac{5}{1}

\text{Number of marchers that were farm-workers}=3500

Therefore, 3500 marchers were farmers.

 

4 0
2 years ago
I need help with it pls
Basile [38]

Answer:

Step-by-step explanation:

Step 1: What are the couch's original coordinates?

  • A: (-4, 2)
  • N: (-4, 3)
  • G: (-1, 3)
  • L: (-1, 4)
  • E: (-5, 4)
  • S: (-5, 2)

Step 2: Rotate the couch 90° counterclockwise.

Rule: (x, y) → (-y, x)

  • A': (-4, 2) → (-2, -4)
  • N': (-4, 3) → (-3, -4)
  • G': (-1, 3) → (-3, -1)
  • L': (-1, 4) → (-4, -1)
  • E': (-5, 4) → (-4, -5)
  • S': (-5, 2) → (-2, -5)

Step 3: Now reflect the "new" couch over the y-axis.

Rule: (x, y) → (-x, y)

  • A'': (-2, -4) → (2, -4)
  • N'': (-3, -4) → (3, -4)
  • G'': (-3, -1) → (3, -1)
  • L'': (-4, -1) → (4, -1)
  • E'': (-4, -5) → (4, -5)
  • S'': (-2, -5) → (2, -5)

Step 4: Finally translate the new new" couch right 1 unit and up 5 units.

Rule: (x + 1, y + 5)

  • A''': (2, -4) → (2 + 1, -4 + 5) → (3, 1)
  • N''': (3, -4) → (3 + 1, -4 + 5) → (4, 1)
  • G''': (3, -1) → (3 + 1, -1 + 5) → (4, 4)
  • L''': (4, -1) → (4 + 1, -1 + 5) → (5, 4)
  • E''': (4, -5) → (4 + 1, -5 + 5) → (5, 0)
  • S''': (2, -5) → (2 + 1, -5 + 5) → (3, 0)

Step 5: Use the distance formula to show that the length of EG is the same as the length of E'''G'''.

  • EG: (-5, 4)(-1, 3)
  • E'''G''': (5, 0)(4, 4)

Distance between E(-5, 4) and G(-1, 3)

  • x₁ = -5
  • x₂ = -1
  • y₁ = 4
  • y₂ = 3

\large \textsf {d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$}\\\\\large \textsf {d = $\sqrt{(-1-(-5))^2+(3-4)^2}$}\\\\\large \textsf {d = $\sqrt{(-1+5)^2+(3-4)^2}$}\\\\\large \textsf {d = $\sqrt{4^2+(-1)^2}$}\\\\\ \large \textsf {d = $\sqrt{16+1}$}\\\\\large \textsf {d = $\sqrt{17}$}\\\\\large \textsf {d = ${4.12}$}

Distance between E'''(5, 0) and G'''(4, 4)

  • x₁ = 5
  • x₂ = 4
  • y₁ = 0
  • y₂ = 4

\large \textsf  {d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$}\\\\\large \textsf {d = $\sqrt{(4-5)^2+(4-0)^2}$}\\\\\large \textsf {d = $\sqrt{(-1)^2+4^2}$}\\\\\large \textsf {d = $\sqrt{1+16}$}\\\\\ \large \textsf {d = $\sqrt{17}$}\\\\ \large \textsf {d = ${4.12}$}

This means that the length of EG is the same as the length of E'''G'''.

Hope this helps!

4 0
2 years ago
When is a rhombus a rectangle?
Alinara [238K]
Check the picture below.

a rhombus is a quadrilateral with all equal sides.

now, the sides do not have to be slanted, but they must be equal, IF it happens that all sides meet at right-angles, then the rhombus is a "rectangle", due to its right-angleness, incidentally enough, since all sides are equal, if that ever happens, it also becomes a square.

6 0
3 years ago
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The answer is d. -14 + (-6)
8 0
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125 i believe i’m not sure
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