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2 years ago

4z-(-3z) can you help me

Mathematics

1 answer:

Korvikt [17]2 years ago

8 0

Answer:

Step-by-step explanation:

4z-(-3z).

Two negatives equal a positive only <u>when they are right next to each other.</u>

4z+3z=7z. Hope this helps :D

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Answer:

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Step-by-step explanation:

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2 years ago

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Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

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3 years ago

Find the quadratic equation whose roots are -3 and 1

Dmitrij [34]

Answer:

x²+2x-3=0

According to Vieta's formula:

x²-(Sum of roots)x+(product of roots)=0

Sum of roots=-3+1=-2

Product of roots=-3×1=-3

The equation is x²-(-2)x+(-3)=0

x²+2x-3=0

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1 year ago

Find the slope of the line passing through the points (7, 8) and (-7, 1). Show your work.

anygoal [31]

Answer:

The slope is $\frac{1}{2}$

Step-by-step explanation:

∵ The rule of the slope passing through 2 points is:

m = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

∵ The points are (7 , 8) and (-7 , 1)

∴ m = $\frac{1-8}{-7-7}=\frac{-7}{-14}=\frac{1}{2}$

4 0

2 years ago

4z-(-3z) can you help me​

4z-(-3z) can you help me