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2 years ago

A candle is 6 inches tall and burns 1/2 inch per hour

Mathematics

1 answer:

Sloan [31]2 years ago

8 0

Answer:

that would take 12 hours to burnt the 6inch candle

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Calculate the sales tax for each item.

Brilliant_brown [7]

Answer:

1. $1.19

2. $2.25

3. $8.40

4. $120

5. $2.10

Step-by-step explanation:

Multiply the money by the sales tax. Calculators help.

3 0

2 years ago

Read 2 more answers

A person invest $2,940 in an account tgat earns 4.1% annual intrest. Find when the value of the investment reaches 5,000. If nec

serg [7]

Answer:

13.22

Step-by-step explanation:

were solving for t and we know:

a(t)=p(1+(r/n))^nt

5000=a-the total

2940=p-the starting amount

.041=r-the rate

1=n-compound (annual)

plug this into a graph :

5000=2940(1+(.041/1))^x

and you get : 13.22

7 0

3 years ago

Help with the this question pleaseeee

34kurt

Answer:

32x - 8

Step-by-step explanation:

A = LW

A = (8x - 2)(4)

A = 32x - 8

7 0

3 years ago

Read 2 more answers

The number of oranges purchased varies directly as the price of the oranges. If 11 oranges cost $2.35, what is the cost of 18 or

lara31 [8.8K]

Answer:

If 11 oranges cost $2.35, then the cost of 18 oranges is $3.84.

Step-by-step explanation:

We have,

The number of oranges purchased varies directly as the price of the oranges.

If the cost of 11 oranges is $2.35.

It is required to find the cost of 18 oranges.

As their is direct relation between number and oranges and price.

So,

The cost of 1 orange is $ $\dfrac{2.35}{11}$ .

For finding the cost of 18 oranges, multiply 18 by $ $\dfrac{2.35}{11}$ such that,

$C=18\times \dfrac{2.35}{11}\\\\C=3.84$

So, If 11 oranges cost $2.35, then the cost of 18 oranges is $3.84.

4 0

3 years ago

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

2 years ago