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icang [17]
3 years ago
10

Suppose an empty flatbed railroad car sits on a track as shown below, with a person pulling on a rope with a force of 310 Newton

s in a direction of θ=25∘. Since the railroad car can't move in the direction that the person is pulling, not all of the force he is exerting works to move the car down the track. How much force is the person exerting toward the right (the force that would go towards trying to move the car)?  ____Newtons    The first person wasn't able to move the railroad car. Suppose a second rope is attached as shown below, and someone pulls on the rope in the direction β=18∘ south of east. If it takes 620 N to get the railroad car moving (even if only slightly), how much force must the second person exert in the given direction to get the railroad car to move? _____ Newtons​

Mathematics
1 answer:
Lelechka [254]3 years ago
3 0

Answer:

Step-by-step explanation:

a) 310cos25 = 281 N

b) (620 - 281) / cos-18 = 356 N

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A club decides to sell T-Shirts for 15$ as a fund-raiser. It cost $20 plus $9 per T-Shirt to make them. How many T-Shirts need t
8090 [49]
The expression for T-shirt production is 20+9T
The expression for total price of selling the T-shirts is 15T

Profit = Total cost of selling - Total cost of buying
Profit = 15T - (20+9T)
Profit = 15T - 20 - 9T
Profit = 6T - 20 

To make profit ≥150

6T - 20 ≥ 150
6T ≥ 170
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The minimum number of T-shirts needed is 29 T-shirts
7 0
3 years ago
Check all that apply. <br> if secØ= 13/12, then:
makvit [3.9K]

Based on <em>trigonometric</em> formulas, we can find that the options that applies to the given <em>trigonometric</em> relationship are tan θ = 5/12 and cos θ = 12/13.

<h3>How to find the exact form of trigonometric functions</h3>

There six <em>trigonometric</em> functions, which are related by a group of expressions, which will be used in this question:

\cos \theta = \frac{1}{\sec \theta} = \frac{12}{13}

\sin \theta = \sqrt{1 - \cos^{2}\theta}

\sin \theta = \sqrt{1 -\left(\frac{12}{13} \right)^{2}}

\sin \theta = \frac{5}{13}

\csc \theta = \frac{1}{\sin \theta} = \frac{13}{5}

\tan \theta = \sqrt{\sec^{2}\theta - 1}

\tan \theta = \sqrt{\left(\frac{13}{12} \right)^{2}-1}

\tan \theta = \frac{5}{12}

Based on <em>trigonometric</em> formulas, we can find that the options that applies to the given <em>trigonometric</em> relationship are tan θ = 5/12 and cos θ = 12/13.

<h3>Remark</h3>

The statement is incomplete. Complete form is shown below:

<em>Check all that apply: </em>

<em />

<em>If sec θ = 13/12, then: </em>

<em />

<em>a) sin θ = 12/13</em>

<em>b) tan θ = 5/12</em>

<em>c) cos θ = 12/13</em>

<em>d) csc θ = 12/13</em>

To learn more on trigonometric equations: brainly.com/question/22624805

#SPJ1

5 0
2 years ago
PLS HELP ASAP ILL GIVE BRAINLKEST THANKS 10 POINTS
Anestetic [448]

#5 Option B

y=(5/4)(4)

= 20/4

=5

#6 Option B

y=2(1)

=2

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3 years ago
What is 0.1 subtracted from 0.01
Law Incorporation [45]
Answer:

-0.09

Explanation
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3 years ago
Maria had 4 full cement blocks and one that was 5/9 the normal size if each full block weighed 3 8/9 pounds what is the weight
Vsevolod [243]

Answer:

17 and 58 over 81 pounds

Step-by-step explanation:

7 0
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