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3 years ago

Giving brainliest !!!!!

Mathematics

1 answer:

Orlov [11]3 years ago

7 0

Answer:

therefore the surface area of this triangular prism is 396 mm2

I hope this helps:)

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If a polynomial function f(x) has roots 3 and StartRoot 7 EndRoot, what must also be a root of f(x)?

Ivenika [448]

Answer:

–√(7) must also be a root of f(x)

Step-by-step explanation:

Given that the roots of an equation is 3 and √(7). This means that x = 3 or √(7). Therefore, the function is definitely going to be:

f(x) = (x – 3)(x² – 7)

This is because we are dealing with √(7) and what brought about √(7) was x² = 7.

If this is the case, we know that x² = 7 will give

x = ±√(7)

Hence, our roots are x = 3 or √(7) or –√(7). Therefore, –√(7) must also be a root of f(x).

4 0

3 years ago

Read 2 more answers

How do u find the point in a graph if they are not given to u when u solving changing y over changing x

stiks02 [169]

U would replace x with 0 in the equation and solve and then do the same but with y and those are ur x and y values of ur point
Ex: 2x+5y=15
2(0) +5y=15
5y=15
Y=3
2x+5(0)=15
2x=15
X=7.5
So ur point would be (7.5,3)

3 0

3 years ago

How do you find The value of a parallelogram

lina2011 [118]

The formula is A=B*H (A=BxH)

4 0

3 years ago

Zahir made this wooden perch for his pet bird. What is the volume of the bird perch? Round to the nearest tenth if necessary.

Nonamiya [84]

Answer:

675

Step-by-step explanation:

3 0

3 years ago

Say that a supplier claims they are 99% confident that their products will be in the interval of 50.02 to 50.38. You take sample

nydimaria [60]

Answer:

The supplier becomes less accurate than they otherwise would have tried to claim. A further explanation is below.

Step-by-step explanation:

According to the provider, this same width of that same confidence interval would be as follows:

= $50.38 - 50.02$

= $0.36$

Depending on the input observed, the width including its confidence interval would be as follows:

= $50.39 - 50.01$

= $0.38$

As even the width of that interval again for survey asserted > the width including its confidence interval according to the provider's statement, we could conclude that such is the appropriate reaction.

3 0

3 years ago