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3 years ago

If a polynomial function f(x) has roots 3 and StartRoot 7 EndRoot, what must also be a root of f(x)?

Mathematics

2 answers:

irakobra [83]3 years ago

8 0

Answer:

Step-by-step explanation:

Edge 2021

Ivenika [448]3 years ago

4 0

Answer:

–√(7) must also be a root of f(x)

Step-by-step explanation:

Given that the roots of an equation is 3 and √(7). This means that x = 3 or √(7). Therefore, the function is definitely going to be:

f(x) = (x – 3)(x² – 7)

This is because we are dealing with √(7) and what brought about √(7) was x² = 7.

If this is the case, we know that x² = 7 will give

x = ±√(7)

Hence, our roots are x = 3 or √(7) or –√(7). Therefore, –√(7) must also be a root of f(x).

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The students' attitudes were measured by administering the Computer Anxiety Rating Scale (CARS). A random sample of 11 nursing s

Fofino [41]

Answer:

There is enough evidence to claim that population mean 1 is less than population 2 at the 0.05 significance level.

Step-by-step explanation:

We are given the following in the question:

Group 1:

$\mu_1 = 63.3\\\sigma_1 = 3.7\\n_1 = 11$

Group 2:

$\mu_2 = 70.2\\\sigma_2 = 6.6\\n_2 = 13$

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu_1 \geq \mu_2\\H_A: \mu_1 < \mu_2$

Since, the population variances are equal and that the two populations are normally distributed, we use t-test(pooled test) for difference of two means.

Formula:

Pooled standard deviation

$s_p = \sqrt{\displaystyle\frac{(n_1-1)\sigma_1^2 + (n_2-1)\sigma_2^2 }{n_1 + n_2 - 2}}$

$t_{stat} = \displaystyle\frac{\mu_1-\mu_2}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

$\text{Degree of freedom} = n_1 + n_2 - 2$

Putting all the values we get:

$s_p = \sqrt{\displaystyle\frac{(11-1)(3.7)^2 + (13-1)(6.6)^2 }{11 + 13 - 2}} = \sqrt{29.9827} = 5.48$

$t_{stat} = \displaystyle\frac{63.3-70.2}{5.48\sqrt{\frac{1}{11}+\frac{1}{13}}} = -3.073$

$\text{Degree of freedom} = 11 + 13 - 2 = 22$

Now,

$t_{critical} \text{ at 0.05 level of significance, 22 degree of freedom } = -1.717$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject the null hypothesis. We accept the alternate hypothesis.

We conclude that the mean score for Group 1 is significantly lower than the mean score for Group 2.

There is enough evidence to claim that population mean 1 is less than population 2 at the 0.05 significance level.

6 0

3 years ago

The lengths of the sides of a triangle are y, y+2, and 8 centimeters. If the perimeter is 34 centimeters, what is the value of y

Aleks04 [339]

Answer: 12

Step-by-step explanation:

OKAYOKAY so what I did was 34 - 8 = 26

then 26 - 2= 24

THEN I divided 24 in to 2 equal parts and got 12 so that means y = 12

Hope that helps!!! :}

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Nookie1986 [14]

Answer:

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Group B is farther from camp.

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