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nevsk [136]
3 years ago
7

If a polynomial function f(x) has roots 3 and StartRoot 7 EndRoot, what must also be a root of f(x)?

Mathematics
2 answers:
irakobra [83]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Edge 2021

Ivenika [448]3 years ago
4 0

Answer:

–√(7) must also be a root of f(x)

Step-by-step explanation:

Given that the roots of an equation is 3 and √(7). This means that x = 3 or √(7). Therefore, the function is definitely going to be:

f(x) = (x – 3)(x² – 7)

This is because we are dealing with √(7) and what brought about √(7) was x² = 7.

If this is the case, we know that x² = 7 will give

x = ±√(7)

Hence, our roots are x = 3 or √(7) or –√(7). Therefore, –√(7) must also be a root of f(x).

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Perform the indicated operation.<br><br> 4/11 · 10/8<br><br> 4/11<br> 5/11<br> 6/11
Dimas [21]
4/11 * 10/8

Multiplying fractions
1) multiply the numerators: 4 * 10 = 40
2) multiply the denominators: 11 * 8 = 88
3) simplify the fraction
40/88 ⇒ 10/22 ⇒ 5/11

40 ÷ 4 = 10
88 ÷ 4 = 22

10 ÷ 2 = 5
22 ÷ 2 = 11

4/11 * 10/8 = 5/11
7 0
3 years ago
Find the unit rate of 3÷12​
yKpoI14uk [10]

Answer:

1/4

Step-by-step explanation:

3/12

Simplify. Both numbers can be divided by 3.

3/12 = 1/4

8 0
3 years ago
Read 2 more answers
Solve the inequality 11 &lt; x - 16
asambeis [7]

Answer:

The choice B.

x > 27

Step-by-step explanation:

11 < x - 16 \\ 11 + 16 < x - 16 + 16 \\ 27 < x \\ x > 27

I hope I helped you^_^

8 0
2 years ago
Solve for x: 3|x-3| 2=14<br> a. No solution<br> b. x=-1,x=8.3<br> c. x=0,x=7<br> d. x=-1,x=7
VMariaS [17]
I am looking  on the answers, and there is only one case, when a or b or c or d pass:   3|x-3| + 2 = 14.  So I assume, that before two is plus. Then:

3|x-3|+2=14    |minus 2
3|x-3|=12        |divide 3
|x-3|=4 

From absolute value definition you've got two ways:

x-3=4     or     x-3=-4
x=7        or     x=-1

And  answer d) passes

3 0
3 years ago
2m=-6n-5 literal equation
Bingel [31]

Answer:

read below

Step-by-step explanation:

Alright, archtan /  

tan

−

1

(

x

)

is the inverse of tangent. Tan is  

sin

cos

. Like the inverse of sin, the inverse of tan is also restricted to quadrants 1 and 4.

Knowing this we are solving for the inverse of tan -1. We are basically being asked the question what angle/radian does tan(-1) equal. Using the unit circle we can see that tan(1)= pi/4.

Since the "Odds and Evens Identity" states that tan(-x) = -tan(x). Tan(-1)= -pi/4.

Knowing that tan is negative in quadrants 2 and 4. the answer is in either of those two quadrants. BUT!!! since inverse of tan is restricted to quadrants 1 and 4 we are left with the only answer -pi/4.

the answer is m=-3n-5/2 or n=2m+5/6

8 0
3 years ago
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