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2 years ago

If a polynomial function f(x) has roots 3 and StartRoot 7 EndRoot, what must also be a root of f(x)?

Mathematics

2 answers:

irakobra [83]2 years ago

8 0

Answer:

Step-by-step explanation:

Edge 2021

Ivenika [448]2 years ago

4 0

Answer:

–√(7) must also be a root of f(x)

Step-by-step explanation:

Given that the roots of an equation is 3 and √(7). This means that x = 3 or √(7). Therefore, the function is definitely going to be:

f(x) = (x – 3)(x² – 7)

This is because we are dealing with √(7) and what brought about √(7) was x² = 7.

If this is the case, we know that x² = 7 will give

x = ±√(7)

Hence, our roots are x = 3 or √(7) or –√(7). Therefore, –√(7) must also be a root of f(x).

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determine whether the lines intersect and if so find the point of intersection and the cosine of the angle of intersection x=4t+

Fittoniya [83]

Answer:

As the lines are not intersecting nor parallel, they must be skew.

Step-by-step explanation:

Question is incomplete, we consider the nearest match available online.

Parametric equations of two lines are:

L₁ : x=4t+2 , y = 3 , z =-t+1

L₂: x=2s+2 , y= 2s+5 , z = s+1

If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

$4t+2=2s+2 ---(1)\\ \\3=2s+5---(2) \\\\-t+1=s+1---(3)$

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

$From (3)\\-t=s\\From (2)\\\\s=\frac{3-5}{2}\\\\s=-1\\\implies t=1\\\\To\,\,check\,\, the \,\,values \,\,of \,\,s\,\, and \,\,t \,\,for\,\,intersection\,\,put \,\,them\,\, in\,\, (1)\\\\4(1)+2= 2(-1)+2\\ 6\ne0$

Hence the lines are not intersecting nor parallel, they must be skew.

6 0

2 years ago

What is the value of the 3 in 8.139

Fofino [41]

The 8 is in the ones place.

The 1 is in the tenths place.

The 3 is in the hundredths place.

The 9 is in the thousandths place.

hope it helps!

6 0

3 years ago

The graph of a sinusoidal function intersects its midline at (0,5) and then has a maximum point at (\pi,6)

Natalija [7]

First, let's use the given information to determine the function's amplitude, midline, and period.

Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.

Finally, we should determine the parameters of the function's formula by considering all the above.

Determining the amplitude, midline, and period

The midline intersection is at y=5 so this is the midline.

The maximum point is 1 unit above the midline, so the amplitude is 1.

The maximum point is π units to the right of the midline intersection, so the period is 4 * π.

Determining the type of function to use

Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function.

This means there's no horizontal shift, so the function is of the form -

a sin(bx)+d

Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.

The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1.

The midline is y=5, so d=5.

The period is 4π so b = 2π / 4π = 1/2 simplified.

$f(x)1 sin (\dfrac{1}{3}x) +5$ = Solution

8 0

2 years ago

11 + (3)(9)

vodka [1.7K]

Answer:

B- In Step 2, the associative property cannot regroup addition and multiplication.

8 0

3 years ago

Read 2 more answers

Solve the equation. show all work<br><br> 18^(r-10)=93

Elina [12.6K]

Recall the logarithm rules :

a^y = x is the same as log_a x = y

In this case,

a = 18
y = r - 10
x = 93

So,

18^ (r-10) = 93

is the same as

log_18 93 = r - 10

Solve for r to get :

10 + log_18 93 = r

3 0

3 years ago