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makkiz [27]
3 years ago
6

Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle betwee

n the sides a and b of ∆ABC is more than 90°? area of square c2 = -area of square a2 − area of squareb2 + area of defect1 + area of defect2 area of square c2 = area of square a2 + area of squareb2 + area of defect1 − area of defect2 area of square c2 = area of square a2 + area of squareb2 − area of defect1 − area of defect2 area of square c2 = area of square a2 + area of squareb2 + area of defect1+ area of defect2 area of square c2 = area of square a2 − area of squareb2 + area of defect1 − area of defect2
Mathematics
1 answer:
horrorfan [7]3 years ago
4 0
Asked and answered elsewhere.
brainly.com/question/1410592

_____
Google doesn't recognize the terms "defects method" except in association with various postings of this same problem.
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The area of a square can be represented by the expression x10. The side of the square can be written in the form xn.
Valentin [98]

The complete answer

The answer is 5


4 0
2 years ago
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Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc
Anna11 [10]

Answer:

The final velocity v is 21.74 m/s.

Step-by-step explanation:

Given:

\textrm{initial velocity} = u = 9\ m/s\\\textrm{acceleration} = a = 7\ m/s^{2}\\\textrm{distance} = s = 28\ m

To find:

\textrm{final velocity} = v = ?

Solution:

As we know the third equation of motion is represented as

v^{2} = u^{2} + 2\times a\times s\\

Substituting the values u, a and s in the above equation we get

v^{2} = 9^{2} + 2\times 7\times 28\\ =81 + 392\\=473\\

v =\±\sqrt{473} \\v =\sqrt{473} \ \textrm{as acceleration is positive v is also positive}\\v = 21.74\ m/s

7 0
3 years ago
The price of a visit to the dentist is \$50$50dollar sign, 50. If the dentist fills any cavities, an additional charge of \$100$
liubo4ka [24]
An expression for the cost will be 50+100n, where n is the number of cavities.
6 0
3 years ago
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Y = - |x+3| - 4<br><br><br> It needs to be graphed, please help!
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

7 0
3 years ago
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How to do this question plz answer ​
ANEK [815]

9514 1404 393

Answer:

  more than half are being used

Step-by-step explanation:

Perhaps easiest to understand is the most straightforward: figure the total number of seats and the number of seats being used. Check to see if that is more than half.

The 1 first-class carriage has usage of ...

  (3/8)(64 seats) = 24 seats.

The 6 standard carriages have usage of ...

  (7/13)(6 · 78 seats) = 252 seats.

The total number of seats used is ...

  24 + 252 = 276 . . . . seats used

__

The total number of seats on the train is ...

  1·64 +6·78 = 532 . . . . seats on the train

Half of the seats on the train will be ...

  532/2 = 266 seats . . . . half the seats

The 276 used seats are more than half of the total number. More than half the seats are being used.

_____

<em>Alternate solution</em>

Another way to look at this is to compare utilization to 1/2 in each carriage class.

  In first class 1/2 -3/8 = 1/8 of 64 seats = 8 seats fewer than 1/2 the seats are being used.

  In standard class, 7/13 -1/2 = 14/26 -13/26 = 1/26 of 78 seats = 3 seats more than 1/2 the seats are being used. There are 6 standard class carriages, so 6·3 = 18 more than half the seats in the standard-class carriages are being used.

This number is 10 more than the 8 under-utilized seats in first class, so <em>more than half the train seats are being used</em>.

8 0
2 years ago
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