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makkiz [27]
3 years ago
6

Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle betwee

n the sides a and b of ∆ABC is more than 90°? area of square c2 = -area of square a2 − area of squareb2 + area of defect1 + area of defect2 area of square c2 = area of square a2 + area of squareb2 + area of defect1 − area of defect2 area of square c2 = area of square a2 + area of squareb2 − area of defect1 − area of defect2 area of square c2 = area of square a2 + area of squareb2 + area of defect1+ area of defect2 area of square c2 = area of square a2 − area of squareb2 + area of defect1 − area of defect2
Mathematics
1 answer:
horrorfan [7]3 years ago
4 0
Asked and answered elsewhere.
brainly.com/question/1410592

_____
Google doesn't recognize the terms "defects method" except in association with various postings of this same problem.
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3 years ago
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PLZZZZZ HELP MEH ILLLL MARK AND 100 points
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Answer:

Volume of original toolbox = 180 in³

Yes, doubling one dimension only would double the volume of the toolbox.

Step-by-step explanation:

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proof:

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A swimming pool is to be constructed in a 1,408-ft2 backyard. There is to be a fence that will surround a 12-by-24-foot pool. Th
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The width of the pool is 10 feet.

<h3>What is area of rectangle?</h3>

The area of rectangle is product of length and breadth.

Let the width be x.

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We know, area= 1408 ft².

(12 + 2x)(24 + 2x) = 1408

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