Let x = length of the park
Let y = width of the park
Because the area is 392392 ft², therefore
xy = 392392 (1)
Because three sides of fencing measure 5656 ft, therefore
2x + y = 5656 (2)
That is
y = 5656 - 2x (3)
Substitute (3) into (1).
x(5656 - 2x) = 392392
5656x - 2x² = 392392
2x² -5656x + 392392 = 0
x² - 2828x + 196196 = 0
Solve with the quadratic formula.
x = (1/2)*[2828 +/- √(2828² - 4*196196)]
= 2756.83 or 71.17
Answer:
The possible dimensions are 2756.8 ft and 71.2 ft (nearest tenth)
Answer:
Your question is VERY hard to read so I'm gonna take the points and go..
Yes because then there would be no support therefore ya know you’d fall to the ground.
Answer:
justin 10+ Amy 20 + henry 40+ do answer would be 10+20+50=70
explanation
I took justin and timed it by two then half of 20 is 10 then timed it by two again which 20*2 is 40
add it all together and you get 70
Answer:
huh? it would be 30% the instructions are a little unclear
