Volume of a cone, V = πr^2h/3
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
Answer:
yes it's right tick it right one
I got 25/21 or 1 4/21, but there’s a possibility I could’ve made a mistake in my math so you should double check it just in case.
The answer would be 2 hope this helps