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daser333 [38]
3 years ago
9

What is 4 over 25 as a decimal

Mathematics
1 answer:
kotykmax [81]3 years ago
5 0
The answer is:
4/25 is the same as saying 16/100 (you do it the easy way because its obvious). Thus, you have 16 over 100. That's 16 one-hundredths. .16 is your answer. 

<span>Or you simply divide the denominator into the numerator (the bottom into the top) like this: 4 divided by 25, which will give you the same answer: .16
</span>Hope this helpes!   :3
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Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
katrin2010 [14]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31.4 or higher are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 5.3

Identify the test scores that are significantly low or significantly high.

Significantly low

Z = -2 and lower.

So the significantly low scores are thoses values that are lower or equal than X when Z = -2. So

Z = \frac{X - \mu}{\sigma}

-2 = \frac{X - 20.8}{5.3}

X - 20.8 = -2*5.3

X = 10.2

Test scores of 10.2 or lower are significantly low.

Significantly high

Z = 2 and higher.

So the significantly high scores are thoses values that are higherr or equal than X when Z = 2. So

Z = \frac{X - \mu}{\sigma}

2 = \frac{X - 20.8}{5.3}

X - 20.8 = 2*5.3

X = 31.4

Test scores of 31.4 or higher are significantly high.

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3 years ago
A new car is purchased for 19000 dollars. The value of the car depreciates at 11.25% per year. What will the value of the car be
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Answer:

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Step-by-step explanation:

Convert 11.25% to the decimal fraction 0.1125.  Then subtract this result from 1.0000:  0.8875.

After 14 years, the formerly $19000 car will have the value

$19000(0.8875)^14 = $3573. 64

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a) the independent variable is the number of training miles.

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3 years ago
This is a bit confusing for me, can anyone help me out?
AnnZ [28]

Answer:

circumference=471

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circumference=150pi=150*3.14=471

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