Question

The area of a rectangle is 70 in 2 and the length of the rectangle is 3 in. Longer than the width

Answer 1

Alright, lets get started.

I hope, the dimensions of rectange are asked in this question.

Suppose the width of rectangle = x in

Given that length of the rectangle is 3 in longer than the width.

It means length of the rectangle = (x+3) in

Now, the area of the rectangle = lenght * width

area of the rectangle = $x * (x+3)$

area of the rectangle =$x^2+3x$

The area of a rectangle is 70 in square (given in question)

Equalling both areas

$x^2 + 3x = 70$

Subtracting 70 in both sides

$x^2 + 3x - 70 = 70 - 70$

$x^2 + 3x - 70 = 0$

Factoring

$(x-7)(x+10) = 0$

It will give two values of x

x = -10 (which is not possible because length could not be negative)

x = 7

Means width $= 7 in$

length $= 7 + 3 = 10 in$

Means the dimensions of rectangle are 7 in and 10 in. : Answer

Hope it will help :)