Using the z-distribution, as we are working with a proportion, it is found that 1016 constituents are required.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
The margin of error is given by:
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
The estimate is of 
, while the margin of error is of M = 0.03, hence solving for n we find the minimum sample size.
Rounding up, 1016 constituents are required.
More can be learned about the z-distribution at brainly.com/question/25890103
Answer: The probability that both televisions work is 0.5625 .
The probability at least one of the two televisions does not work is 0.4375.
Step-by-step explanation:
Given : Number of televisions received in shipment= 12
Number of defective televisions received in shipment= 3
Then proportion of defective televisions =
Using binomial probability formula, the probability of getting success in x trials is given by :-
If two televisions are randomly selected, then the probability that both televisions work will be :-
The probability at least one of the two televisions does not work will be :-
Answer:
it will be 0.44%
Step-by-step explanation:
Answer:
188π in^2
Step-by-step explanation:
Surface area of the rocket = surface area of the cone + surface area of the cylinder
Surface area of a cone = πr(r+h^2+r^2)
r = 8/2 = 4 in
4π( 4 + 3^2 + 4^2) =
4π ( 4 + 9 + 16) = 116π in^2
Surface area of a cylinder = 2πrh+2πr^2
(2 x n x 4 x 5) + (2 x n x 16)= 72π in^2
116 + 72 = 188π in^2
