Question

Helps plz,

Answer 1

$\huge \mathrm{Answer࿐ }$

Fig - 1 : Rectangle

• length = 3x + x = 4x

• width = x + x = 2x

$\boxed{\mathrm{Area = length \times width}}$

• $4x \times 2x$

• $8 {x}^{2}$

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Fig - 2 : Kite

$\boxed{\mathrm {Area = \dfrac{1}{2} \times d_1 \times d_2 }}$

• $\dfrac{1}{2} \times 4x \times 2x$

• $4 {x}^{2}$

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Area of shaded region :

• Area of rectangle - Area of kite

• $8 {x}^{2} - 4 {x}^{2}$

• $4 {x}^{2}$

So, Correct option is B. 4x²

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$\mathrm{ \#TeeNForeveR}$

Answer 2

Here's the solution,

there's a rectangle with sides 4x and 2x

So, area of rectangle :

=》4x × 2x

=》8x²

now, let's divide the kite into two equal triangles with base = 4x

and height = x

area of each triangle :

=》

$\dfrac{1}{2} \times base \times height$

=》

$\dfrac{1}{2} \times 4x \times x$

=》

$2x \times x$

=》

$2{x}^{2}$

now, area of each triangle = 2x²

and there are two triangles so,

Area of the kite will be :

=》2 × 2x²

=》4x²

Area of shaded region =

=》Area of rectangle - Area of kite

=》8x² - 4x² = 4x²

hence, correct option is B.