First put it in decreasing power according to x.
x^4-5x+8+x^2
=x^4+x^2-5x+8
Now this question is asking what is the highest degree of x you see in this function.
4 of course.
Therefore the answer to his question is degree of 4.
Done!
Answer:
(a) 0.5899
(b) 0.9166
Step-by-step explanation:
Let X be the random variable that represents the height of a woman. Then, X is normally distributed with
= 62.5 in
= 2.2 in
the normal probability density function is given by
, then
(a) 
= 0.5899
(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)
(b) We are seeking 
where n = 37. 
is normally distributed with mean 62.5 in and standard deviation 
. So, the probability density function is given by
, and
= 0.9166
(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))
You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.
Answer:
to get our answer, we multiply the two fractions together. 6/8× 3/5= 3/5 or 0.6
hope this helps! mark me brailyest please :D
Answer:
i'm not too good in this, but i believe the answer is -3
Step-by-step explanation:
the hcf, highest common factor, of both -3 and -15 is -3, hence making the answer -3? if this is incorrect, i apologize.
Item 4 Find the median, first quartile, third quartile, and interquartile range of the data. 132,127,106,140,158,135,129,138 med
Ket [755]
Answer:
133.5, 127.5, 139.5, 12
Step-by-step explanation:
order data:
106, 127, 129, 132, 135, 138, 140, 158
Median:
The middle number: (8+1)/2 = 4.5 between the 4&5 numbers
= (135-132)/2= 1.5
1.5 + 132 = 133.5
lower quartile (1st quartile):
(8+1)/4 = 2.25 between the 2&3 numbers
(129+127)/4=0.5
0.5+127 = 127.5
upper quartile(3rd quartile):
(8+1)/4 x3 = 6.75 between the 6&7 numbers
(140-138)/4 x3 = 1.5
1.5 + 138 =139.5
Interquartile range:
139.5-127.5= 12
hope this helps
