All categories

3 years ago

A rectangle has a perimeter of 196 meters and a length of 50 meters.What is the width of the rectangle? Explain.

1 answer:

3 0

Answer: 48 meters

we already know that one side is 50 m, so since it's a
rectangle you can multiply 50 by 2 which gives you 100. Know you have two sides left (which would be the same number) . You can do it easy and subtract 196 and 100 which gives you 96. Then, divide 96 by 2 and you get 48.

---- check: do 48(2)+50(2) it will give you 196

HOPE THIS HELPED

You might be interested in

(06.04 MC)

Andru [333]

$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

◉ $\large\bm{ -4}$

$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

Before performing any calculation it's good to recall a few properties of integrals:

$\small\longrightarrow \sf{\int_{a}^b(nf(x) + m)dx = n \int^b _{a}f(x)dx + \int_{a}^bmdx}$

$\small\sf{\longrightarrow If \: a \angle c \angle b \Longrightarrow \int^{b} _a f(x)dx= \int^c _a f(x)dx+ \int^{b} _c f(x)dx }$

So we apply the first property in the first expression given by the question:

$\small \sf{\longrightarrow\int ^3_{-2} [2f(x) +2]dx= 2 \int ^3 _{-2} f(x) dx+ \int f^3 _{2} 2dx=18}$

And we solve the second integral:

$\small\sf{\longrightarrow2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot(3 - ( - 2)) }$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} 2dx = 2 \int ^3_{-2} f(x)dx + 2 \cdot5 = 2 \int^3_{-2} f(x)dx10 = }$

Then we take the last equation and we subtract 10 from both sides:

$\sf{{\longrightarrow 2 \int ^3_{-2} f(x)dx} + 10 - 10 = 18 - 10}$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 8}$

And we divide both sides by 2:

$\small\longrightarrow \sf{\dfrac{2 { \int}^{3} _{2} }{2} = \dfrac{8}{2} }$

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx=4}$

Then we apply the second property to this integral:

$\small \sf{\longrightarrow 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx + 2 \int ^3_{-2} f(x)dx = 4}$

Then we use the other equality in the question and we get:

$\small\sf{\longrightarrow 2 \int ^3_{-2} f(x)dx = 2 \int ^3_{-2} f(x)dx = 8 + 2 \int ^3_{-2} f(x)dx = 4}$

$\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =4}$

We substract 8 from both sides:

$\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx -8=4}$

• $\small\longrightarrow \sf{2 \int ^3_{-2} f(x)dx =-4}$

7 0

2 years ago

3x - 12y = 6<br> x - 4y = 2<br> solve by elimination

OverLord2011 [107]

Answer:

the problem has an infinite number of solutions

Explanation:

3x - 12y = 6

x - 4y = 2

make the coefficient of x same by multiplying the entire following by 3

⇒ ( x - 4y = 2 ) * 3

⇒ 3x - 12y = 6 __ equation 2

3x - 12y = 6 __ equation 1

solving using elimination method:

3x - 12y = 6

===========

5 0

2 years ago

Read 2 more answers

What is the square root of 121

Dvinal [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What does x equal? Plz hurry. First to answer correctly will be marked brainliest ASAP.

svet-max [94.6K]

Answer:

6.0

Step-by-step explanation:

This involves using SOH CAH TOA.

we use Sin as we want to find x (which is side O, and we are given H).

So we get sin37 = O/H

= x/10

so x = 10 sin 37 = 6.018... = 6.0 to the nearest tenth.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20" id="TexFormula1" title=" " alt=" " align="absmiddle" class="latex-formula"><br><img src="

seropon [69]

$\text{The range of}\ y=-3^x\ \text{is}\ (-\infty;\ 0).\\\\\text{The range of}\ f(x)=-3^x+7\ \text{is}\ (-\infty;\ 7)$

6 0

3 years ago