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tatiyna
3 years ago
7

Which of the four Venn diagrams represent (X U Y)?

Mathematics
1 answer:
dusya [7]3 years ago
8 0
X or Y diagram is the answer to this question
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Base area: 12.5 m2; height: 1.2 m
Novay_Z [31]

Answer:

Volume = 150 m^2

Step-by-step explanation:

Using Volume formula of prism, we get L*W*H, but since we know the area of the base is L*W, which is 12.5, we multiply 12.5 by 12 to get 150 m^2.

7 0
3 years ago
9x = 63 what is x<br> <img src="https://tex.z-dn.net/?f=9x%20%3D%2063" id="TexFormula1" title="9x = 63" alt="9x = 63" align="abs
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x = 7

Step-by-step explanation:

Please give me brainliest :)

5 0
2 years ago
HELP WILL GIVE BRAINLY PL. What is the sign of f3•(-g)^3?
Nastasia [14]

Answer:

Negitive

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Diane averages 10 mph riding her
aksik [14]

Answer:

20 miles

Step-by-step explanation:

d miles × (1 h)/(10 miles) = d/10 hours

d miles × (1 h)/(40 miles) = d/40 hours

d/40 = d/10 - 3/2

d = 4d - 60

d = 20 miles

4 0
3 years ago
A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr
ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so \pi = 0.30

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so n = 10

We want to find P(X = 1). So:

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is P(X > 1)

We have that:

P(X \leq 1) + P(X > 1) = 1

P(X > 1) = 1 - P(X \leq 1)

We also have that:

P(X \leq 1) = P(X = 0) + P(X = 1)

P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282

So

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493

Finally

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507

There is a 85.07% probability that more than 1 has the marker.

3 0
3 years ago
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