Find the product 7 x 300 = hundreds
2 answers:
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Answer:
C. x^2 + 2x - 1 = 3
Step-by-step explanation:
The standard form of a quadratic equation is
ax^2 + bx + c = 0
We need to use the quadratic formula and the given expression to find the values of a, b, and c.
The quadratic formula is
Where the formula has -b, the problem has -2, so b = 2.
Now we have
ax^2 + 2x + c = 0
In the denominator, where the formula has 2a, the problem has 2(1), so a = 1.
Now we have
x^2 + 2x + c = 0
Inside the root, the quadratic formula has -4ac. the problem shows -4(1)(-4). Since we already know that a = 1, then c = -4.
Now we have
x^2 + 2x - 4 = 0
Let's look at choice A.
x^2 + 1 = 2x - 3
Subtract 2x from both sides. Add 3 to both sides.
x^2 - 2x + 4 = 0 <em>This is not it!</em>
Let's look at choice B.
x^2 - 2x - 1 = 3
Subtract 3 from both sides.
x^2 - 2x - 4 = 0 <em>This is not it!</em>
Let's look at choice C.
x^2 + 2x - 1 = 3
Subtract 3 from both sides.
x^2 + 2x - 4 = 0 <em>This is it!</em>
Answer: C. x^2 + 2x - 1 = 3
Answer:
(0.53 > 0.51) both less than 1 while 5 is greater than both
Step-by-step explanation:
and 5
the number line has two sides, with the left side for negative numbers while the right side is for positive numbers.
<u> </u>
-5 -4 -3 -2 -1 -.53 -.51 0 .51 .53 1 2 3 4 5
By studying the number line above all decimal numbers greater than 0 but less than 1 are from 0, .1, .2,.........,.98, .99, 1.00 which is also the same as 1 because all numbers greater than 1 has an invisible point at its right side like 2., 3. which also means 2, 3 while negative number are all less than 0