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yan [13]
3 years ago
15

Determine the total number of roots of each polynomial function. f (x) = 3x^4 + 1)^2

Mathematics
2 answers:
sineoko [7]3 years ago
5 0
f ( x) = ( 81 x+ 1 ) ^ 2
f ( x) = 6561 x + 2

or f (x ) = 81 ^2 x + 2
bixtya [17]3 years ago
4 0
F=3x^4+1/x is the answer i got. try too use mathpapa.com if you can

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Answer:

78.38

Step-by-step explanation:

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Complete the table.<br> f(y) = 4y2 - 4v<br> f(v<br> -4<br> -3<br> -2<br> -1
Nastasia [14]

Answer:

f(y) = 4y2 - 4v

f(y) = 4y² - 4(-4) = 4y² + 16

f(y) = 4y² - 4(-3) = 4y² + 12

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Step-by-step explanation:

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3 years ago
An introductory psychology class has 9 freshman males, 15 freshman females, 8 sophomore males, and 12 sophomore females. A rando
inessss [21]

Answer

16/43

Step-by-step explanation:

17 Male + 27 female = 44 students

now n= 2 so first student was male so one male student was taken out of the equation so 16 male left. now left male students by remaining students  so now total left students = 43

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4 0
2 years ago
I need help with a math equation, it’s due by 3:00.
Vilka [71]

Answer:

         2x        -7

2x      4x²      -14x

-1       -2x        +7

Step-by-step explanation:

4x²-16x+7 factors as

(2x-7)(2x-1)

So the grid would be:

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4 0
2 years ago
An electronics firm claims that the proportion of defective units of a certain process is 5%. A buyer has a standard procedure o
lesya692 [45]

Answer:

0.0006 = 0.06% probability of this occurrence

Step-by-step explanation:

For each unit, there are only two possible outcomes. Either it is defective, or it is not. The probability of an unit being defective is independent of any other unit, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

An electronics firm claims that the proportion of defective units of a certain process is 5%.

This means that p = 0.05

A buyer has a standard procedure of inspecting 15 units selected randomly from a large lot.

This means that n = 15

a) What is the probability of this occurrence?

Probability of 5 defective items, whch is P(X = 5). So

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P(X = 5) = C_{15,5}.(0.05)^{5}.(0.95)^{10} = 0.0006

0.0006 = 0.06% probability of this occurrence

8 0
3 years ago
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