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3 years ago

I need help with Geometry

Mathematics

1 answer:

Katarina [22]3 years ago

5 0

Answer:

x=2, mn=ol=7

Step-by-step explanation:

by definition of a parallelogram we can see that the 2 lines are equal and therefore x+5=2x+3 which we can solve and get x=2. We can put the x=2 back into either line to solve since the 2 lines have equal length. Done!

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Please answer my question

Ghella [55]

Interval notation uses parenthesis and brackets, while inequality notation uses inequality symbols.

Interval notation: [-4, 8)

Inequality notation: $-4\leq x$

x >= -4, x < 8

---For inequality notation, it can also be written as two separate inequalities. I am not sure what your teacher is looking for, so I will provide both the compound and separate formats.

Interval notation: (-infinity, 7)

Inequality notation: x < 7

Interval notation: (-infinity, -6) U (0, infinity)

Inequality notation: $-6> x \geq 0$

x < -6, x >= 0

Hope this helps!

8 0

3 years ago

Four boxes of cookies were sold to a family of five each box contains 12 cookies if each family member ate 2 cookies from each b

Delvig [45]

Answer:B

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Write the polynomial in factored form. p(x)=(x+5)(x-___)(x+___)

Rom4ik [11]

Answer:

Step-by-step explanation:

Given : $p(x)=x^{3} +6x^{2} -7x-60$

Solution :

Part A:

First find the potential roots of p(x) using rational root theorem;

So, $\text{Possible roots} =\pm\frac{\text{factors of constant term}}{\text{factors of leading coefficient}}$

Since constant term = -60

Leading coefficient = 1

$\text{Possible roots} =\pm\frac{\text{factors of 60}}{\text{factors of 1}}$

$\text{Possible roots} =\pm\frac{1,2,3,4,5,6,10,12,15,20,60}{1}$

Thus the possible roots are $\pm1, \pm2, \pm 3, \pm4, \pm5,\pm6, \pm10, \pm12, \pm15, \pm20, \pm60$

Thus from the given options the correct answers are -10,-5,3,15

Now For Part B we will use synthetic division

Out of the possible roots we will use the root which gives remainder 0 in synthetic division :

Since we can see in the figure With -5 we are getting 0 remainder.

Refer the attached figure

We have completed the table and have obtained the following resulting coefficients: 1 , 1,−12,0. All the coefficients except the last one are the coefficients of the quotient, the last coefficient is the remainder.

Thus the quotient is $x^{2} +x-12$