No, Brianna is not correct.
The distance around the pool is 131.4 ft
Step by step explanation:
1) Semi circle with a diameter equal to the side opposite it, 20 ft.
Find the length of half the circle:
Circumference of semi-circle = (1/2)(πd)
Where:
π = 3.14
d = 20 ft.
Circumference of semi-circle = (1/2)(3.14)(20 ft) = 31.4 ft.
2) Vertical lengths from the endpoint of semi-circle to the endpoints of horizontal lengths, 40 ft each ⇒ 2 × 40 ft. = 80 ft.
3.) Horizontal length at 20 ft.
Add the semi-circle, vertical, and horizontal lengths:
Distance around the pool = 31.4 ft + 80 ft. + 20 ft.
Distance around the pool = 131.4 ft.
B^2 = a^2 + c^2 - 2ac sin B
is the answer
PENTA = 5.
a regular polygon has all equal sides, so if one side is 5.8, all are, so the perimeter for this pentagon with 5 sides is 5.8 + 5.8 + 5.8 + 5.8 + 5.8 = 29.
Slayyyyytyyyyyyyyyyyyyyyyyyyy
For what value of x does 32x - 93x-4 ?
