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expeople1 [14]
2 years ago
7

A scientist is comparing the sequences of related genes among three species. Two of the species have very similar sequences, whi

le the sequence of the third species differs greatly from the others. T
Biology
1 answer:
Elena-2011 [213]2 years ago
5 0

Hi. The question you presented above is incomplete. This makes it impossible for this question to be answered. However, when searching for your question on the internet, I was able to find another question exactly like yours, which asked you to explain the evolutionary relationship between these three species. If that's the case for you, I hope the answer below will help you.

In a simplified way, we can infer that among the three species presented above, the third presented a faster evolution than the first two and this is what explains the difference between the gene sequences between the species. As the question presents, the three species have related genes, which indicates that they had a common ancestor, however the difference in the gene sequence of the third species shows that it evolved first, showing changes that cannot be noticed in the first two species that are evolving more slowly.

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Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based
zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values ​​can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

p^{2} = f(TLTL)

2pq = f(TSTL)

q^{2} = f(TSTS)

So, if the population is in balance:

P = p^{2}

H = 2pq

Q = q^{2}

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

f(TLTL) = P = p^{2} = 0,4^{2} = 0,16

f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48

f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36

I hope you have a SUPER day!

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Answer:

When the rule of 70 applies to population, dividing 70 by the percentage of population growth should equal the time (in years) that the population needs to be double (option A)

Explanation:

The rule of 70 is useful to calculate the time in which a variable of any type can be duplicated. The calculation is done by dividing the number 70 by the percentage of growth of the variable.

<u>If the rule of 70 is applied to the population, it is possible to calculate, based on its growth rate, the time that population would need to double</u>.

If, for example, the growth rate of a population is 3 percent:

70 / 3 = 23,33

This indicates that a population, with a growth rate of 3% would need about 23,33 years to double.

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