Question

A rigid container of O 2 has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273°C ?

Answer 1

Answer:

260 kPa

Explanation:

To answer this problem we can use Gay-Lussac's law, which states that at a constant volume (such as is the case with a rigid container):

• P₁T₂=P₂T₁

Where in this case:

• P₁ = 340 kPa

• T₂ = 273 °C ⇒ 273 + 273.16 = 546 K

• P₂ = ?

• T₁ = 713 K

We input the data:

• 340 kPa * 546 K = P₂ * 713 K

And solve for P₂:

• P₂ =  260 kPa