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Nezavi [6.7K]
4 years ago
9

A sample of C3H8 has 8.08 × 1024 H atoms.

Chemistry
2 answers:
quester [9]4 years ago
5 0
(8.08x10^24 H atoms)(3 C atoms/8 H atoms)
=3.03x10^24 C atoms
3.03x10^24+8.08x10^24=1.111x10^25 atoms total
(1.111x10^25)/(6.02x10^23)=18.4551495 mol C3H8
18.4551495(44.01)=812.2111296g C3H8
Alchen [17]4 years ago
3 0

Answer:

3.03\times 10^{24} atoms of carbon in the sample.

73.7960 grams is the total mass of the sample.

Explanation:

Compound = C_3H_8

Total numbers of hydrogen atoms in a compound = 8.08\times 10^{24} atoms

In one molecule of compound there are 8 hydrogen atoms.

Then x number of molecules of compound having 8.08\times 10^{24} hydrogen atoms.

x=\frac{8.08\times 10^{24}}{8} molecules=1.01\times 10^{24} molecules

In one molecule of compound there are 3 carbon atoms.

Then 1.01\times 10^{24} molecules of given compound will have :

3\times 1.01\times 10^{24} atoms=3.03\times 10^{24} atoms of carbon

3.03\times 10^{24} atoms of carbon in the sample.

Moles of given compounds = n

x=N_A\times n

n=\frac{N_A}{x}=\frac{1.01\times 10^{24}}{6.022\times 10^{23} mol^{-1}}

n = 1.6771 moles

Mass of 1.6771 moles of given compound:

1.6771 mo\times (3\times 12 g/mol+8\times 1 g/mol)=73.7960 g

73.7960 grams is the total mass of the sample.

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SCORPION-xisa [38]

Answer:

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Explanation:

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3 years ago
Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold
Mama L [17]

<u>Answer:</u> The number of gold atoms per cubic centimeters in the given alloy is 1.83\times 10^{22}

<u>Explanation:</u>

To calculate the number of gold atoms per cubic centimeters for te given silver-gold alloy, we use the equation:

N_{Au}=\frac{N_AC_{Au}}{(\frac{C_{Au}M_{Au}}{\rho_{Au}})+(\frac{M_{Au}(100-C_{Au})}{\rho_{Ag}})}

where,

N_{Au} = number of gold atoms per cubic centimeters

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C_{Au} = Mass percent of gold in the alloy = 42 %

\rho_{Au} = Density of pure gold = 19.32g/cm^3

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M_{Au = molar mass of gold = 196.97 g/mol

Putting values in above equation, we get:

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NOF : Dipole-dipole forces

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Explanation:

London dispersion forces exist in all substances

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C2H6 : London dispersion forces because all dipole-dipole forces are cancelled out due to the symmetry of the molecule

H2O : Hydrogen bonding between hydrogen and oxygen and the assymetry of the molecule

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