Question

A sample of C3H8 has 8.08 × 1024 H atoms.

Answer 1

(8.08x10^24 H atoms)(3 C atoms/8 H atoms)
=3.03x10^24 C atoms
3.03x10^24+8.08x10^24=1.111x10^25 atoms total
(1.111x10^25)/(6.02x10^23)=18.4551495 mol C3H8
18.4551495(44.01)=812.2111296g C3H8

Answer 2

Answer:

$3.03\times 10^{24} atoms$ of carbon in the sample.

73.7960 grams is the total mass of the sample.

Explanation:

Compound = $C_3H_8$

Total numbers of hydrogen atoms in a compound = $8.08\times 10^{24}$ atoms

In one molecule of compound there are 8 hydrogen atoms.

Then x number of molecules of compound having $8.08\times 10^{24}$ hydrogen atoms.

$x=\frac{8.08\times 10^{24}}{8} molecules=1.01\times 10^{24} molecules$

In one molecule of compound there are 3 carbon atoms.

Then $1.01\times 10^{24} molecules$ of given compound will have :

$3\times 1.01\times 10^{24} atoms=3.03\times 10^{24} atoms$ of carbon

$3.03\times 10^{24} atoms$ of carbon in the sample.

Moles of given compounds = n

$x=N_A\times n$

$n=\frac{N_A}{x}=\frac{1.01\times 10^{24}}{6.022\times 10^{23} mol^{-1}}$

n = 1.6771 moles

Mass of 1.6771 moles of given compound:

$1.6771 mo\times (3\times 12 g/mol+8\times 1 g/mol)=73.7960 g$

73.7960 grams is the total mass of the sample.