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Tasya [4]
3 years ago
8

Calculate the number of moles of solute present and the number of grams

Chemistry
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

The answer is: 18 moles and 1341, 72 grams of KCl

Explanation:

The molarity is defined as the moles of solute ( in this case KCl) in 1 liter of solution:

1L solution-----3 moles of KCl

6L solution-----x= (6L solutionx 3 moles of KCl)/1 L solution= <em>18 moles of KCl</em>

<em></em>

We calculate the weight of 1 mol of KCl:

Weight 1 mol KCl= Weight K + Weight Cl= 39,09 g + 35, 45 g=74, 54 g/mol

1 mol KCl----- 74, 54 g

18 mol KCl----x= (18 mol KCl x 74, 54 g)/1 mol KCl=<em>1341, 72 g</em>

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4 0
2 years ago
35.5 moles of lithium fluoride is dissolved in 65 L of solution
kkurt [141]

Answer:

Explanation:

L

=

1.10

L

of solution

Explanation:

The Molarity

M

is calculated by the equation comparing moles of solute to liters of solution

M

=

m

o

l

L

For this question we are given the Molarity 0.88M

We are told the solute is a 25.2 gram sample of LiF, Lithium Fluoride

We can convert the mass of LiF to moles by dividing by the molar mass of LiF

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25.2

g

r

a

m

s

x

1

m

o

l

25.94

g

r

a

m

s

=

0.97

moles

Now we can take the the molarity and the moles and calculate the Liters of solution

M

=

m

o

l

L

M

L

=

m

o

l

L

=

m

o

l

M

L

=

0.97

m

o

l

0.88

M

L

=

1.10

L

of solution i just did look at my papaer

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Answer:

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