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Ainat [17]
3 years ago
12

Please help I will mark brainly

Chemistry
1 answer:
wolverine [178]3 years ago
8 0
The first one i think
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33 protons 36 electrons 45 neutrons
Artist 52 [7]

As has an atomic number of 33, so it has 33 protons.  

It has a charge of 3-, so there are three more electrons than protons. Thus, there are 36 electrons.  

It has a mass of 75, which is the sum of neutrons and protons.  

33+n=75 ---> n = 75 - 33 = 42 neutrons  

The answer is e) 33 protons, 42 neutrons and 36 electrons.

6 0
3 years ago
A student analyzes soil samples from her backyard. She organizes the samples into three categories, based on their pH. The three
Sedaia [141]
I think the best answer is the last option. A scatter plot is the appropriate type of graph for the student to use to show the percent samples per group. This plot is somewhat similar to line graphs. However, they are use for  a specific purpose which is to show the relationship between two parameters. In this case, the correlation between pH and the percent of samples.
5 0
3 years ago
Read 2 more answers
If 200 mg of HCl is added to water to achieve a final volume of 1L, what is the final pH?
Anvisha [2.4K]

hope this helps ..................

8 0
3 years ago
Read 2 more answers
A chemist added an excess of sodium sulfate to a solution of a soluble barium compound to precipitate all of the barium ions as
grigory [225]

Answer:

  259.497 mg,   58.84%

Explanation:

BaSO₄ → Ba²⁺ + SO₄²⁻

to calculate the mole of BaSO₄

mole BaSO₄ = mass given / molar mass = 403 mg / 233.38 g/mol = 1.7268 mol

comparing the mole ratio

1.7268 mol of BaSO₄ yields 1.7268 mol of Ba²⁺

403 mg BaSO₄  yields     ( 1.7268 × 137.327 ) where 137.327 is the molar mass of Barium mol of Ba²⁺

441 mg BaSO₄  will yield   ( 1.7268 × 137.327  × 441 mg ) / 403 mg = 259 .497 mg

mas percentage of the Barium compound = 259 .497 mg / 441 mg × 100 = 58.84%

8 0
3 years ago
Titanium metal is used as a structural material in many high-tech applications such as in jet engines.
Elza [17]

Answer:

a.Cp=0.523

b.Cp=25.02\frac{J}{mol^\circ C}

Explanation:

a. First, we solve the specific heat equation as follows:

Q=mCp\Delta T\\Cp=\frac{Q}{m\Delta T}\\Cp=\frac{89.7J}{33.0g\times5.20^\circ C}=0.523

b. Then, we use the molar mass of titanium to determine its molar heat capacity, as follows:

Cp=0.523\frac{J}{g^\circ C}\times 47.87\frac{g}{mol}\\Cp=25.02\frac{J}{mol^\circ C}

3 0
3 years ago
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