A vet borrows $12,000 for 4 years. The total interest paid was $875. What was the interest rate on the loan?

I have many students are represented in the data set?

nalin [4]

Answer:

a) 19 students

b) the mean 3 9/19

the median 3

the mode 3

c) the range 6

Step-by-step explanation:

The data set shows that

0 points gets 1 student,

1 point gets 1 student,

2 points get 2 students,

3 points get 6 students,

4 points get 4 students,

5 points get 3 students and

6 points get 2 students.

a) There are 1+1+2+6+4+3+2=19 students.

b) The mean is

$\dfrac{1\cdot 0+1\cdot 1+2\cdot 2+6\cdot 3+4\cdot 4+3\cdot 5+2\cdot 6}{19}=\dfrac{66}{19}=3\dfrac{9}{19}.$

The average score is 3 9/19 points.

The median is 10th term in the data set - 3 points (means the middle score in the data set)

The mode is 3 points (means most happened score)

c) The range of the data is 6-0=6 points.

7 0

2 years ago

If f(x) = (x + 9 and g(x) = --6, which describes the range of (f + g)(x)?

S_A_V [24]

Given:

Consider the below figure attached with this question.

To find:

The value of $(f+g)(x)$ .

Solution:

The given functions are:

$f(x)=|x|+9$

$g(x)=-6$

Now,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=|x|+9+(-6)$

$(f+g)(x)=|x|+9-6$

$(f+g)(x)=|x|+3$

We know that,

$|x|\geq 0$

Adding 3 on both sides, we get

$|x|+3\geq 0+3$

$(f+g)(x)\geq 3$

So, $(f+g)(x)\geq 3$ for all values of x.

Hence, the correct option is A.

6 0

2 years ago

Mariko and her friend spent $24.50 on

jolli1 [7]

For the lunch it would be 20$

4 0

2 years ago

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Using a linear approximation, estimate f(2.1), given that f(2) = 5 and f'(x) = √3x-1.

algol [13]

Answer:

$f\left( {2.1} \right) \approx 5.22360$ .

Step-by-step explanation:

The linear approximation is given by the equation

${f\left( x \right) \approx L\left( x \right) }={ f\left( a \right) + f^\prime\left( a \right)\left( {x - a} \right).}$

Linear approximation is a good way to approximate values of $f(x)$ as long as you stay close to the point $x= a$ , but the farther you get from $x=a$ , the worse your approximation.

We know that,

$a=2\\f(2) = 5\\f'(x) = \sqrt{3x-1}$

Next, we need to plug in the known values and calculate the value of $f(2.1)$ :

${L\left( x \right) = f\left( 2 \right) + f^\prime\left( 2 \right)\left( {x - 2} \right) }=5+\sqrt{3(2)-1}(x-2) =5+\sqrt{5}(x-2)$

Then

$f\left( {2.1} \right) \approx 5+\sqrt{5}(2.1-2)\approx5.22360$ .

6 0

2 years ago

What is the value of the fourth term in a geometric sequence for which a1 = 30 and r = 1/2?

Pani-rosa [81]

Answer: The required fourth term of the geometric sequence is $\dfrac{10}{9}.$

Step-by-step explanation: We are given to find the value of the fourth term in a geometric sequence with first term and common ratio as follows :

$a(1)=30,~~~~~r=\dfrac{1}{2}.$

We know that

the n-th term of a geometric sequence with first term a1 and common ratio r given by

$a(n)=a(1)r^{n-1}.$

Therefore, the fourth term of the given geometric sequence will be

$a(4)=a(1)r^{4-1}=30\times r^3=30\times\left(\dfrac{1}{3}\right)^3=\dfrac{30}{27}=\dfrac{10}{9}.$

Thus, the required fourth term of the geometric sequence is $\dfrac{10}{9}.$

7 0

2 years ago

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