Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
The answer to your question is: 85°
Step-by-step explanation:
Data
m∠ xyz = 2m∠x - 9
m∠w = 38°
Process
∠x = (∠xyz + 9) / 2
∠ y = 180 - ∠xyz
∠w + ∠y + ∠x = 180
Substitution 38 + (180 - ∠xyz) + (∠xyz + 9) / 2 = 180
76 + 360 - 2∠xyz + ∠xyz + 9 = 360
Simplify
85 - 2∠xyz + ∠xyz = 0
85 = ∠ xyz
There is no image? Please input an image so I can try to help :)
It’s a function
hope you have a good day
