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erica [24]
2 years ago
6

CE and FH are parallel lines. Which angles are supplementary angles?

Mathematics
2 answers:
nadya68 [22]2 years ago
6 0

Answer:

<CDG and <CDB are supplementary angles.

Nataly_w [17]2 years ago
3 0

Answer:

hff

Step-by-step explanation:

< CDG and <CDB are supplementary angles.

msm555 is correct

hope it is helpful to you ☺️☺️☺️

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Which method of multiplication is shown below?
Ilya [14]

The method of multiplication shown is (a) Ancient Egyptian Method

<h3>Multiplication</h3>

This involves taking the product of at least two factors which could be numbers, expressions or both

From the method shown, we can see that a factor is multiplied by multiples of 2 (i.e. doubling), till it reaches a maximum

This method is associated with the Egyptian.

Hence, the method of multiplication is (a) Ancient Egyptian Method

Read more about multiplications at:

brainly.com/question/10873737

4 0
2 years ago
Who is 5 times 3 related to 5 / 1/3
olya-2409 [2.1K]

Answer:

5 times 3 and 5 divide by 1/3  yield the same result - see below.

Step-by-step explanation:

When we divide by a fraction we invert it and then multiply so:

5 / 1/3

= 5 * 3/1

= 5 * 3.

3 0
3 years ago
What's 2x1 1/4x1 1/2 <br> I need this answer
kolezko [41]
The answer would be 3.75
8 0
3 years ago
Read 2 more answers
PLEASE HELP I NEED TO PASS <br> “Solve for output, find f(x)=4x-3”
katrin2010 [14]

Answer:

-12

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Show all work to multiply (6+square root -64)(3-square root -16)
Hunter-Best [27]

Answer:

50

Step-by-step explanation:

- 8i = √-64

8i + 6

- -4i = -√-16

-4i + 3

[8i + 6][-4i + 3] → FOIL

>> -32i² + [24i - 24i] + 18

↑ ↑

-1 0

>>> 32 + 18 = 50

Information on Imaginary Numbers

√-1 = i

-1 = i²

-i = i³

1 = i⁴ [And every other exponent that is a multiple of 4; this cycle then repeats itself every time you go up one number at a time]

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

7 0
2 years ago
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