Answer:
4:4
Step-by-step explanation:
3:3 can be simplified to 1:1 ( divide by 3) and then to 4:4( multiply by 4)
Hope this helps :D please mark brainliest if correct
A set of ordered pairs, like the ones shown, represents a function only if each of the first coordinates is not repeated.
For example {(2, 5), (7, 8)} is a function, but {(2, 3), (6, 8), (2, -1)} is not because 2 is repeated.
We can check that each set of pairs we are given, are functions.
The inverses of each of these sets would be :
<span>{(–2, –1), (4, 0), (3, 1), (14, 5), (4, 7)} 4 repeats
{(2, -1), (4, 0), (5, 1), (4, 5), (2, 7)} 4 and 2 repeat
{(3, -1), (4, 0), (14, 1), (6, 5), (2, 7)} no repetition of 1st coordinates
{(4, -1), (4, 0), (2, 1), (3, 5), (1, 7)} 4 repeats
</span>
So only the inverse of <span>{(–1, 3), (0, 4), (1, 14), (5, 6), (7, 2)} is also a function</span>
The answer is 16,300. To get the answer, you just move the decimal over 4 places to the right and add your zeros in.
hopefully this helps
Answer:
On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4
Step-by-step explanation:
The given function is presented as follows;
From the given function, we have;
When x = 1, the denominator of the fraction, 
, which is (x - 1) = 0, and the function becomes, 
therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote
Also we have that in the given function, as <em>x</em> increases, the fraction tends to 0, therefore as x increases, we have;
Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1
When -∞ < x < 1, we also have that as <em>x</em> becomes more negative, f(x) → 4. When x = 0, 
. When <em>x</em> approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left
Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.
