Mitchell purchased a car in 2008 for $25,980. The function y 25,980(0.88y represents the depreciated value of the car after t ye
1 answer:
Answer:
Step-by-step explanation:
we know that
The exponential decay function that represent the depreciated value of the car is given by
where
y is the depreciated value of the car
t is the number of years since 2008
What is the approximate value of the car in 2012?
Find the value of t
substitute in the equation
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Answer:
The line of best fit
y = 0.633x + 0.561
Step-by-step explanation:
The coordinates that the dart hit include
(–5, 0), (1, –3), (4, 5), (–8, –6), (0, 2), and (9, 6)
The x and y coordinates can be written as
x | y
-5|0
1 | -3
4|5
-8|-6
0|2
9|6
So, running the analysis on a spreadsheet application, like excel, the table of parameters is obtained and presented in the first attached image to this solution.
Σxᵢ = sum of all the x variables.
Σyᵢ = sum of all the y variables.
Σxᵢyᵢ = sum of the product of each x variable and its corresponding y variable.
Σxᵢ² = sum of the square of each x variable
Σyᵢ² = sum of the square of each y variable
n = number of variables = 6
The scatter plot and the line of best fit is presented in the second attached image to this solution
Then the regression analysis is then done
Slope; m = [n×Σxᵢyᵢ - (Σxᵢ)×(Σyᵢ)] / [nΣxᵢ² - (∑xi)²]
Intercept b: = [Σyᵢ - m×(Σxᵢ)] / n
Mean of x = (Σxᵢ)/n
Mean of y = (Σyᵢ) / n
Sample correlation coefficient r:
r = [n*Σxᵢyᵢ - (Σxᵢ)(Σyᵢ)] ÷ {√([n*Σxᵢ² - (Σxᵢ)²][n*Σyᵢ² - (Σyᵢ)²])}
And -1 ≤ r ≤ +1
All of these formulas are properly presented in the third attached image to this answer
The table of results; mean of x, mean of y, intercept, slope, regression equation and sample coefficient is presented in the fourth attached image to this answer.
Hope this Helps!!!
