Alright, lets get started.
Please see the diagram I have attached.
If the length of the square = s
The perimeter of the square will be = 4s
So, if the length is given of a square = 7 inches
The perimeter of that square will be =
So, the perimeter of the square will be = 28 inches. : Answer
Hope it will help you.:)
Answer:
56,50,07,16,60
Step-by-step explanation: The students are numbered from 01-90, each number is a student, therefore you can't have any repeating numbers in your answer.
Answer:
8x2y - 6x2 - 8xy2 - y2
Step-by-step explanation:
Equation at the end of step 1 :
(((((5•(x2))•y)-(5•(x2)))+(3y•(x2)))-(3•(y2)))-((((x2)+(y2))+(8x•(y2)))-3y2)
Step 2 :
Equation at the end of step 2 :
(((((5•(x2))•y)-(5•(x2)))+(3y•(x2)))-(3•(y2)))-((((x2)+(y2))+23xy2)-3y2)
Step 3 :
Equation at the end of step 3 :
(((((5•(x2))•y)-(5•(x2)))+(3y•(x2)))-3y2)-(x2+8xy2-2y2)
Step 4 :
Equation at the end of step 4 :
(((((5•(x2))•y)-(5•(x2)))+3x2y)-3y2)-(x2+8xy2-2y2)
Step 5 :
Equation at the end of step 5 :
(((((5•(x2))•y)-5x2)+3x2y)-3y2)-(x2+8xy2-2y2)
Step 6 :
Equation at the end of step 6 :
((((5x2•y)-5x2)+3x2y)-3y2)-(x2+8xy2-2y2)
Step 7 :
Final result :
8x2y - 6x2 - 8xy2 - y2
What it is basically asking is if Y = -4, find the value of x in the equation 6x + 7y = 4x + 4y
To solve this you just need to plug in -4 for y and solve for x
6x + 7(-4) = 4x + 4(-4)
6x - 28 = 4x - 16
Now isolate x by adding 28 to both sides
6x - 28 + 28 = 4x - 16 + 28
6x = 4x + 8
and subtract 4x from both sides
6x - 4x = 4x - 4x + 8
2x = 8
divide both sides by 2
2/2x = 8/2
x = 4
x = 4, y = -2
Answer: (4, - 2)
Hope it helps :)
Bransliest would be appreciated
1<em>.) </em><em>Reduction</em>
<em>As you can see Triangle A was reduced in size as a result of Triangle B</em>
<em>2.) </em><em>Enlargement</em>
<em>Square A is much smaller than square B, making this an enlargement</em>
<em>3.) </em><em>Enlargement</em>
<em>The quadrilateral shown here gets larger with quadrilateral B</em>
<em>4.) </em><em>Reduction</em>
<em>This object gets vividly smaller as shown on the graph, making it a reduction </em>