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S_A_V [24]
3 years ago
6

Plz i need help asap ill give brainliest Find the area of the shaded regions: ​

Mathematics
2 answers:
sammy [17]3 years ago
7 0

Answer:

I think it's 19.72

Step-by-step explanation:

A = r²· a / 2

Y_Kistochka [10]3 years ago
5 0

Green part is 56.548667772

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Which equation is the inverse of y = 16x2 + 1?
Llana [10]

Answer:

y=\frac{\sqrt{x-1} }{4}

Step-by-step explanation:

The given equation is

y=16x^2+1

For this function to have an inverse, we must restrict the domain, say x\ge0

We interchange x and y to get,

x=16y^2+1


We now make y the subject to get;


x-1=16y^2


x-1=16y^2

We divide through by 16 to get;


\frac{x-1}{16}=y^2


We now take the square root of both sides to get;

\pm \sqrt{\frac{x-1}{16}}=y


y=\pm \frac{\sqrt{x-1} }{4}


Since  x\ge 0, the inverse function is


y=\frac{\sqrt{x-1} }{4}


6 0
4 years ago
Y= -8x + 10/9 what is the y intercept
4vir4ik [10]

Answer:

10/9

Step-by-step explanation:

This equation is in slope-intercept form, this is referring to the y-intercept. Slope-intercept is y=mx+b, where m is the slope and b is the y-intercept. Therefore, 10/9 is the intercept while -8 is the slope.

4 0
3 years ago
I need help with this plz !!!!!!
Alika [10]
2nd one is the correct one I think
5 0
3 years ago
Read 2 more answers
Calculate the force when the pressure is 18 N/M squared and the area is 4 M squared.
Doss [256]
The force is 72 Newton
8 0
3 years ago
In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta
Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.3246

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0
3 years ago
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