Answer:
The P-value for this test is P=0.2415.
Step-by-step explanation:
We have to perform an hypothesis testing on the mean of alla account balances.
The claim is that the mean of all account balances is significantly greater than $1,150.
Then, the null and alternative hypothesis are:

The sample size is n=20, with a sample mean is 110 and standard deviation is 125.
We can calculate the t-statistic as:

The degrees of freedom fot this test are:

For this one-tailed test and 19 degrees of freedom, the P-value is:

( x + 4), (x - 9) = 4x
Hope this helps!
Answer:
11 years approx
Step-by-step explanation:
Given data
P=$1000
A=2000
R=6.5%
T= ?
Calculate time, solve for t
t = ln(A/P) / r
substitute
t=ln(2000/1000)/0.065
t=ln(2)/0.065
t=0.693/0.065
t=10.66
Hence the time is 11 years approx
Answer is 11w-6
Add all the like terms. So all with the w’s which is how I got 11 and then 6 stays the same hence the -6
Answer:
(x + 5)(x + 10) = 0
Step-by-step explanation:
When you solve for the equation:
, you get that the answer is
.
<em>Hope this helped!!</em>