9 is the answer
Step by step
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Okay, all of these pairs add up to 1 or 100%, except for one pair. I'll convert them all to decimals, so all must add up to 1.
3/8 = 0.375
0.625 + 0.375 = 1
62% = 0.62
0.38 + 0.62 = 1
7/8 = 0.875
0.875 + 0.125 = 1
70% = 0.70
1/3 <span>≈</span> 0.33
0.70 + 0.33 = 1.03
So the last pair of probabilities(70%, 1/3) does not belong with the other three because it does not add up to 1 like the others.
A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.
B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4.
(13−10)! 3!
C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =
10! 3!
9!1! 1!2!
10! 3!
8!2! 2!1!
10! 3!
7!3! 3!0!
= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =
= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =
= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285
1·2·3
<span>possible choices.</span><span>
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