First, make a equation in which r= red and b=blue.
So, since in the first box it has 4 red models and one blue model equaling 12,
the first equation looks like 4r+b=12.
The second equation looks like 2r+b=8.
What you would do is try and first solve for r by getting rid of b.
Since both equation has a positive b, you would make one equation have a negative b by multiplying the whole equation by -1.
-1*(2r+b=8)= -2r-b=-8
Add.
4r+b=12
+(-2r-b=-8)
2r=4
r=2
Then, you plug in 2 for the r for any of the original equations.
4(2)+b=12
8+b=12
b=4
or
2(2)+b=8
4+b=8
b=4
So, the red models weigh 2 pounds while the blue models weigh 4.
Answer:
hey,
ur question is wrong,
base of triangle can never be longer than hypotenuse,and you have told base is twice of hypotenuse,
if hypotenuse is twice of base, then solution is give below, in picture,
and answer is 1/2
Answer:
x = - 3 and x = 1
Step-by-step explanation:
Given the rational expression

The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be, that is
x² + 2x - 3 = 0 ← in standard form
(x + 3)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Thus x = 1 and x = - 3 are both excluded values