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yan [13]
3 years ago
6

Use algebra to solve the following question 7x + 3 = -11

Mathematics
1 answer:
meriva3 years ago
3 0

Answer:

x = -2

Step-by-step explanation:

7x + 3 = -11

     -3     -3        subtract both sides by 3

7x = - 14

7x/7 = - 14/7     divide both sides by 7

-14/7 = -2

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Two models of cellular telephones, red and blue, are stored in boxes. One box weighs twelve pounds and contains four of the red
GenaCL600 [577]
First, make a equation in which r= red and b=blue.

So, since in the first box it has 4 red models and one blue model equaling 12,

the first equation looks like 4r+b=12.

The second equation looks like 2r+b=8.

What you would do is try and first solve for r by getting rid of b.

Since both equation has a positive b, you would make one equation have a negative b by multiplying the whole equation by -1.

-1*(2r+b=8)= -2r-b=-8

Add.

4r+b=12
+(-2r-b=-8)

2r=4
r=2

Then, you plug in 2 for the r for any of the original equations.

4(2)+b=12

8+b=12

b=4

or

2(2)+b=8

4+b=8
b=4

So, the red models weigh 2 pounds while the blue models weigh 4.



5 0
3 years ago
The base of a triangle is twice of its hypotenuse.the sin of angle opposite to base is..?
beks73 [17]

Answer:

hey,

ur question is wrong,

base of triangle can never be longer than hypotenuse,and you have told base is twice of hypotenuse,

if hypotenuse is twice of base, then solution is give below, in picture,

and answer is 1/2

3 0
3 years ago
an aviary places an order for 75 pounds of bird seeds. the order is filled by mixing different kinds of seeds from Bin A Bin B a
Alex73 [517]
Where are the options?

6 0
3 years ago
Read 2 more answers
The graph of a quadratic equation opens down when the value of a,b or c <br> Is negative
aleksandr82 [10.1K]

Answer:

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3 0
3 years ago
What is the excluded value of x / x^2 +2x -3​
Rzqust [24]

Answer:

x = - 3 and x = 1

Step-by-step explanation:

Given the rational expression

\frac{x}{x^2+2x-3}

The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be, that is

x² + 2x - 3 = 0 ← in standard form

(x + 3)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x - 1 = 0 ⇒ x = 1

Thus x = 1 and x = - 3 are both excluded values

3 0
3 years ago
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