5x - 8y + 104 = 0 is a linear equation passing through (-8 , 8) and parallel to the line whose equation is 5x - 8y - 7 = 0.
First, for two equations of line to be parallel with each other, their slope must be equal.
Transforming the given equation into slope-intercept form, y = mx + b:
5x - 8y - 7 = 0
8y = 5x - 7
y = 5/8 x - 7/8
m = 5/8
Hence, the slope of our equation should also be 5/8.
Using the again the slope intercept form, solve for b.
y = mx + b
where m = 5/8, x = -8 and y = 8
8 = 5/8 (-8) + b
8 = -5 + b
b = 13
With m= 5/8 and y-intercept, b = 13, the equation of our line is
y = mx + b
y = 5/8 x + 13
Multiplying both sides by 8,
8y = 5x + 104
5x - 8y + 104 = 0
To know more about equation of line, brainly.com/question/13763238.
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Answer: sec^4(x)-tan^4(x) = 1+2 x tan^2(x)
Step-by-step explanation:
Answer:
x = -1.
Step-by-step explanation:
√(x + 10) - 4 = x
√(x + 10) = x + 4
Squaring both sides:
x + 10 = x^2 + 8x + 16
x^2 + 8x - x + 6 = 0
x^2 + 7x + 6 = 0
(x + 6)(x + 1) = 0
<u>x = -6, -1.</u>
Check for any extraneous roots:
√(x + 10) - 4 = x
<u>Try x = -6:</u>
√(-6 + 10) - 4 = 2 - 4 = -2.
but we found x = -6 , so -6 is not a root.
<u>Try x = -1</u>:
√(-1 + 10) - 4 = 3 - 4 = -1. So x = -1 is a root.
1 and 2, because 1+2 is 3, which is less than 6, 2+3 is 5 which is also less than 6.
