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kow [346]
3 years ago
6

Restaurant etiquette dictates that you should have a 15 %

Mathematics
1 answer:
choli [55]3 years ago
5 0
Yes you are right !!!!!
You might be interested in
What’s the correct answer for this?
Mice21 [21]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

First, you'd work out the centre value

It would be the opposite value to what is in the brackets

Thus, the centre value is (2, -4)

Plot this value on a graph

In order to find the radius, you must square root the 25

Thus, the radius would be 5

Plot some points with a radius of 5 from the centre and then draw the circle

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

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8 0
3 years ago
Textbook: Please write as an expression involving functions of Θ alone.
Setler [38]

Step-by-step explanation:

tan(Θ + 30°)

Use angle sum formula:

tan(A + B) = (tan A + tan B) / (1 − tan A tan B)

So we can write this as:

(tan Θ + tan 30°) / (1 − tan Θ tan 30°)

tan 30° = 1/√3, so:

(tan Θ + 1/√3) / (1 − 1/√3 tan Θ)

Multiply top and bottom by √3:

(√3 tan Θ + 1) / (√3 − tan Θ)

6 0
3 years ago
1/2(6 2/3+1/4)-5/24=
Helen [10]

For this case we must simplify the following expression:

\frac {1} {2} (6 \frac {2} {3} + \frac {1} {4}) - \frac {5} {24} =

We convert the mixed number to an improper fraction:

6 \frac {2} {3} = \frac {3 * 6 + 2} {3} = \frac {20} {3}

So, by rewriting we have:

\frac {1} {2} (\frac {20} {3} + \frac {1} {4}) - \frac {5} {24} =\\\frac {1} {2} (\frac {4 * 20 + 3 * 1} {4 * 3}) - \frac {5} {24} =\\\frac {1} {2} (\frac {80 + 3} {12}) - \frac {5} {24} =\\\frac {1} {2} (\frac {83} {12}) - \frac {5} {24} =

\frac {83} {24} - \frac {5} {24} =\\\frac {83-5} {24} =\\\frac {78} {24} =\\\frac {39} {12} =\\\frac {13} {4} =\\3 \frac {1} {4}

Answer:

3 \frac {1} {4}

5 0
3 years ago
Help me Find the area of
andriy [413]
I believe the answer is 4,523. Correct me if im wrong
3 0
3 years ago
Read 2 more answers
Can anyone explain me?​
Alika [10]

Answer:

Step-by-step explanation:

a) (a + b)² = (a + b) * (a +b)

  (a + b)³  = (a + b) * (a +b) * (a +b)

 a²- b² = (a +b) (a - b)

Here (a + b) is common in all the three expressions

HCF = (a + b)

b) (x - 1) = (x - 1)

  x² - 1  = (x - 1) * (x + 1)

  (x³ - 1) = (x - 1) (x² + x + 1)

HCF = (x -1)

7 0
3 years ago
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