12-12 is 0, so -.30(12-12)^2 = 0
c(0) = 40
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
Like what is you trying to say explain
Answer:
x=6
Step-by-step explanation:
you dived the 5 to get x by itself and 5 dived by 30 is 6
A translated expression of the following into words would be
Subtract five x by seven.
Hope this helped :)
