3=3*1
6=3*2
8=2^3
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Multiple of 3 , 6 and 8 is 2^3*3=24 and all his multiples
M24∈{72,96 }
If you drew out this line segment with the points in the order we are given them, the segment would be labeled as a, b, c, d in that order. We are given a measure for ab, and we are also given a measure for bd with c being ignored for a minute. The entire length of the segment can be found by adding ab and bd. 6 + 23 = ad and ad = 29. So the length of the whole segment is 29. We have the length of cd given to be equal to ab, so cd = 6. ab + bc + cd = ad and we are looking for bc. Since we have the other lengths and the length of the whole segment, we fill in accordingly: 6 + bc + 6 = 29. Solving for bc we get bc = 17.
I’m pretty sure the answer is 6.125
Average = mean = sum of the values / number of data
Values = h, j, and k
Number of data = 3
Sum of the values = h + j + k
Mean = [h + j + k] / 3
=> Answer: option c. [h+j+k] over 3
