Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:

Likewise:

Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

Likewise:

Since ∠QAC ≅ ∠PAB:

And by substitution:

Thus:

Then by SAS Congruence:

And by CPCTC:

First let's define vertex: A point on the curve with a local minimum or maximum of curvature. If we look for the minimum and maximum value of the equation y=x^2+5: minimum value X=0, substitute in the equation to get the maximum value of Y y = 0^2 + 5y = 0 + 5y= 5 so the ordered pair is (0,5) Hope That Helped =D
96÷120 =0.8 ⇒0.8 ×100 =80 % :))
Answer:
radius = 13
Step-by-step explanation:
Look at the attached picture below. We can calculate radius with the help of the Pythagorean theorem. But first we have to find out the values of the two legs.
First let's find the shorter leg.
<u>Equidistant Chords Theorem</u>
Two chords are congruent if they are equidistant from the center.
Chords in the picture are congruent and that means that the distance from the center to each of them is the same!
Let's calculate the distance. But to get the distance we have to find x first.
Since the distances are the same:

Therefore:

Let's focus on the longer leg. Since part of the radius is perpendicular to the chord, it actually bisects the chord! That means that the long leg is going to be a half of the length of the chord.
Therefore:

All that is left is the Pythagorean Theorem in the right triangle.
<u>Pythagorean Theorem</u>

Hypotenuse in our case is the radius.

Answer:
it can't be anymore simplified
Step-by-step explanation: