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kow [346]
2 years ago
11

To assess the effectiveness of a kindergarten-readiness program, 15 children from a random sample were each given a diagnostic a

ssessment before beginning the program and a follow-up assessment after completing the program. For each child, the difference in the score points between the two assessments was calculated and used to create the 95 percent confidence interval (20.1,23.9)(20.1,23.9).
Assuming all conditions for inference are met, which of the following is a correct interpretation of the interval?
A) For all children in the program, 95 percent of the children will have a mean difference in scores of between 20.1 points and 23.9 points.
B) There is a 0.95 probability that the mean difference in scores for all children in the sample is between 20.1 points and 23.9 points.
C) There is a 0.95 probability that the mean difference in scores for the children in the program is between 20.1 points and 23.9 points.
D) We are 95 percent confident that the mean difference in scores for all children in the program is between 20.1 points and 23.9 points.
E) We are 95 percent confident that the mean difference in scores for the children in the sample is between 20.1 points and 23.9 points.
Mathematics
1 answer:
kobusy [5.1K]2 years ago
8 0

Answer:

D) We are 95 percent confident that the mean difference in scores for all children in the program is between 20.1 points and 23.9 points.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

95 percent confidence interval (20.1,23.9)

We are 95% sure that the population mean(that is, the mean for all children in the program) is in this interval. So the correct answer is given by option D.

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Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

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Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

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First let's find the shorter leg.

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Chords in the picture are congruent and that means that the distance from the center to each of them is the same!

Let's calculate the distance. But to get the distance we have to find x first.

Since the distances are the same:

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