All categories

2 years ago

Write an exponential function to describe the given sequence of numbers

Mathematics

2 answers:

BabaBlast [244]2 years ago

8 0

Answer:

The next one is 64. Can you mark branliest if it's right?

Solnce55 [7]2 years ago

3 0

Answer:

F(x) = x^1 * 2

Step-by-step explanation:

You might be interested in

4a^5-2a^5+4b+b How to combine this into likewise terms (^number stands for exponents) need help today pls!!!

Nat2105 [25]

Answer: 2a^5+5b

Step-by-step explanation:

This is actually pretty simple

The exponent with the same power can be subtracted so

4a^5-2a^5 is 2a^5 like 4x-2x which is equal to 2x

4b+b is equal to 5b

2a^5+5b is your answer

4 0

3 years ago

I need help....

vredina [299]

Its okay bro, we all failed

7 0

3 years ago

Find the area of a regular decagon with perimeter 100 units. Show all work.

Slav-nsk [51]

A regular polygon has ten (10) equal sides ( since it is regular).
We are given with the perimeter value which is 100 units and the perimeter formula is P = 10a
Solving for a (the side measurement), we have:
100 = 10a
a= 100/10
a =10

We can now proceed in solving the area and the formula is shown below:
Area = 5/2 a√ (5+2√5)
Area = 5/2 * 10√(5+2√5)
Area = 76.94 square units

The answer is 96.94 square units.

4 0

3 years ago

To make a bakery's signature chocolate muffins

garri49 [273]

Become a ninja sneak in and steal their recipe and get out and don't get caught. - VEX

7 0

2 years ago

SHOW YOUR WORK, <br><br>PLEASE HELP!!!!!!!!!

Shkiper50 [21]

To find the inverse, we swap the variables y and x, then solve for the new y.

3a. $y=\frac{3}{x-1}$

Swapping the variables: $x=\frac{3}{y-1}$
Solving for y: $x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}$
The domain of this inverse is $x ≠ 0$ .
3b. $y=x^2-1$

Swapping: $x = y^2 - 1$
Solving for y: $y^2 = x + 1 \\ y = \sqrt{x+1}$
The domain of this inverse is $x ≥ -1$ .
3c. $y=\sqrt[3]{\frac{x-7}{3}}$
Swapping: $x=\sqrt[3]{\frac{y-7}{3}}$
Solving for y: $x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7$
The domain of this inverse is all real numbers.
4a. $y=\frac{3}{x-1}$ , $y=1+\frac{3}{x}$
$y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x$
$y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x$

4c. $y=\sqrt[3]{\frac{x-7}{3}}$ , $y=3x^3+7$
$y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x$
$y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x$

3 0

3 years ago