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Irina18 [472]
3 years ago
9

Find the volume of the cone

Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0

Answer:

gkali 53 *622 kalia qqua 5% habwa

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What is the solution set for 2f ≤ 2?
Firlakuza [10]

Answer:

f ≤ 1

Step-by-step explanation:

I hope this helps, I got a few people to help me and really only remembered the answer so sorry I can't teach you much but I have the answer

6 0
3 years ago
Use the drawing tools to form the correct answer on the provided graph.
ExtremeBDS [4]

Answer:

points are( 6,2),(7,5) and (3,8)

Step-by-step explanation:

X,y changes into y,-X

3 0
3 years ago
Jonathon and Raymond earn a base salary plus commission. Jonathon earns $1500 plus 10% of his sales each month. Raymond earns $1
joja [24]

Answer:

The Jonathon and Raymond need to sell 6000 sales to earn the same amount each month.

Step-by-step explanation:

Given data

Let no. of sales = x

Jonathon earning = $ 1500 + \frac{10}{100} x

Raymond earning = $ 1200 + \frac{15}{100} x

Given that the earnings of Jonathon & Raymond are same.

1500 + \frac{10}{100} x = 1200 + \frac{15}{100} x

300 =  \frac{5}{100} x

x = 6000 sales

Therefore the Jonathon and Raymond need to sell 6000 sales to earn the same amount each month.

4 0
3 years ago
Which phrase describes the algebraic expression 3 x minus 4?
zaharov [31]

Answer:

3x - 4 = -12

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Write the slope-intercept form of the equation of each line 13x-2y=14
HACTEHA [7]

Answer:

Step-by-step explanation:

First, lets put this into y=mx+b form.

You can bring the 13x over to the 14, by subtracting and you get -2y=14-13x, or also -2y = -13x + 14

Then you can divide both sides by -2 to get y, and you get

-2y/-2 = -13x/-2 + 14/-2 which is simplified to y=13/2x + (-7) which is

y=13/2x-7

                                {[( IMPORTANT )]}

 THIS HAS THE SLOPE IN A IMPROPER FRACTION... CHECK IF YOU USE MIXED NUMBERS OR IMPROPER FRACTIONS

the mixed number form is y = 7     1/2 x -7

Hope this helps!

       

7 0
3 years ago
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