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boyakko [2]
3 years ago
10

Find the length of the third side. If necessary, write in simplest radical form.

Mathematics
1 answer:
eduard3 years ago
8 0

Let the third side be x :

( 3√5 )^2 = 6^2 + x^2

45 = 36 + x^2

x^2 = 45 - 36

x^2 = 9

x = 3

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Find the area of a circle with a diameter of 12 in. Rounded to the nearest whole
zheka24 [161]

Answer:

113.04

Step-by-step explanation:

To find the area of a  circle, you multiply 3.14 times the radius squared. To find the radius, you divided the diameter by 2. You get 6. You square 6 and get 36. Multiply that by 3.14 and you'll get 113.04 as your area.

3 0
4 years ago
$34,300 loan at 3.5% for 4 months.
cestrela7 [59]

keeping in mind that 4 months is not even a year, since there are 12 months in a year, 4 months is then 4/12 years.

let's assume is simple interest.


\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$34300\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ t=years\to \frac{4}{12}\dotfill &\frac{1}{3} \end{cases} \\\\\\ A=34300\left[ 1+(0.035)\left( \frac{1}{3} \right) \right]\implies A= 34300(1.011\overline{6})\implies A=34700.1\overline{6}

5 0
3 years ago
100 points.<br> Find the surface area of the triangular prism. The unit is cm^2
nikklg [1K]
First we find the area of the two triangles on each side (keep in mind that they are equal/congruent to each other):

(24*10)/2 = 120 cm^2

Then you find the areas of the three rectangles that are left:

24*19 = 456 cm^2
26*19 = 494 cm^2
10*19 = 190 cm^2

Finally, to find the surface area of the prism:

120+120+456+494+190 = 1,380 cm^2

6 0
3 years ago
Read 2 more answers
6.1.3
Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.  

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.  

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

8 0
3 years ago
The attendance for a team's basketball game can be approximated with the polynomial -5x^2+80x+285, where x is the number of wins
Elan Coil [88]

Answer:

The attendance when the team won 4 games in the previous month is 525

Step-by-step explanation:

The attendance for a team's basketball game can be approximated with the polynomial : -5x^2+80x+285

x represents the number of wins the team had in the previous month.

Factor the polynomial :

-5x^2+80x+285

-5(x^2-16x-57)

-5(x^2-19x+3x-57)

-5(x(x-19)+3(x-19))

-5(x+3)(x-19)

Substitute the value of x = 4

The attendance when the team won 4 games in the previous month = -5(4+3)(4-19)=525

Hence The attendance when the team won 4 games in the previous month is 525

8 0
3 years ago
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