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lilavasa [31]
3 years ago
10

Let's consider a jar consists of 20 marbles. 12 are red and 8 are green. John picked 2 marbles at random. What is the probabilit

y that John picked both the marbles red assuming that the first one is not replaced?
Mathematics
1 answer:
adelina 88 [10]3 years ago
4 0

Answer:   \bold{\dfrac{33}{95}}

<u>Step-by-step explanation:</u>

First pick    and      Second pick      =  Probability

    \dfrac{12\ red}{20\ total}\quad \times    \dfrac{11\ red\ remaining}{19\ total\ remaining}\\  =\dfrac{132}{380}\\  

    Simplify:

 \dfrac{132}{380}\div \dfrac{4}{4}=\large\boxed{\dfrac{33}{95}}\\

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