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3 years ago

24h-36? Need helppp please

1 answer:

7 0

The trick question is that you can’t effect an unknown value because you don’t know what number it is, it has to be a known value, there is nothing that you can do to figure it out, so it’s unknown and cannot be effected.

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30.16=17.56+5x what is the soloution to this equation what is x

skelet666 [1.2K]

Take 30.16-17.56. Theb divide by 5

4 0

3 years ago

Read 2 more answers

ABC is a straight line where BC = 3AB. OA = a, AB = b Express OC in terms of a and b.

Aleks [24]

That would be 3AB because of the expression you have

7 0

2 years ago

julie has 10 yards of ribbon she divides the ribbon into 3 equal pieces and uses 2 of the pieces on gifts how much ribbon does s

Lunna [17]

Answer:

2/3

Step-by-step explanation:

if we divide 10 by 3 then we get 3.3 repeating so just use the fraction 1/3. if you use 2 of the divided lengths then you get 2/3

4 0

3 years ago

I don't understand this question at all please help if you do

lorasvet [3.4K]

Answer:

Answer is $\frac{4}{3}$

Step-by-step explanation:

To find the interval of x. Use our equations to equal each other.

$-x^2+2x=y,y=0$

$-x^2+2x=0\\-x(x-2)=0\\-x=0 , (x-2)=0\\x=0 ,2$

$\int\limits^2_0 {-x^2+2x} \, dx$

Integrate.

$\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3$

Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.

Proof Check your interval of x.

7 0

2 years ago

The angles of elevation froma point X to the top of flagpoles A and B are 35* and 45* respectively. If X lies in the middle of t

BartSMP [9]

Let AB = t. And since X lies in the middle, so AX=BX = t/2 .

Let the height of the smaller flagpole is AO and of larger flagpole is BP .

Using tangent ratio rule in each triangle, we will get

$tan 35 =\frac{AO}{t/2} , tan 45= \frac{BP}{t/2} // AO = \frac{t*tan35}{2}, BP=\frac{t*tan45}{2}$

And there ratio is

$\frac{AO}{BP}= \frac{tan 35}{tan 45}=\frac{0.7}{1}$

5 0

3 years ago