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Law Incorporation [45]
3 years ago
12

Log(x^2– 64) - log(x + 8)

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

log (x - 8).

Step-by-step explanation:

log(x^2– 64) - log(x + 8)

= log[ (x^2 - 64) / (x + 8)]

= log [ (x + 8)(x - 8) / (x + 8)]

= log (x - 8).

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a_{1} = the first term of the series

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a_{1}= k = 235\ ft

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S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{1-\frac{3}{4} }

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{\frac{1}{4} }

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