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Nataly_w [17]
3 years ago
13

A population of 360 field mice live inside of a small area of forest near your house.240 of the mice are brown, and 120 of the m

ice are grey.What is the frequency of grey mice in this population

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0
It would be about 33%
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Help with this one!!!<br><br><br> Show steps pls :)
Flauer [41]

Answer:

20 \times \frac{1}{8}

40

5 0
4 years ago
What is the product of 200 and 100?? Cause I really need to know today
Sauron [17]
Simple, just multiply 2x1=2. And then add the remaining zeros to the end, which would make it 20,000.
7 0
3 years ago
12,000,055 + 60 + 16 + 90 x 40
Naddika [18.5K]

Answer: 12003731

Step-by-step explanation: Hope this helps

7 0
3 years ago
Read 2 more answers
A jeweler is dividing
Anuta_ua [19.1K]

Answer: OPTION D:  \frac{3}{32}

Step-by-step explanation:

By definiton, fractions have the following form:

\frac{a}{b}

Where "a" is called numerator and "b" is the denominator. The numerator and the denominator are Integers.

 In order to solve this exercise you need to remember de Division of fractions:

\frac{a}{b}\div\frac{d}{e}=\frac{a}{b}*\frac{e}{d}=\frac{a*e}{b*d}

In this case, according to the information given in the exercise, you know that \frac{3}{8}\ lb of rubies are divided into 4 lots.

Therefore, in order to calculate the weight in pounds of each lot, you need to divide \frac{3}{8}\ lb  by 4.

Then, you get the following result:

\frac{3}{8}\ lb\div4=(\frac{3}{8}\ lb) (\frac{1}{4})=\frac{3}{8*4}\ lb=\frac{3}{32} \ lb

As you can notice, this result matches with the Option D.

5 0
3 years ago
The square of X varies inversely as the square root of Y and directly as the variable M. When M = 27 and Y = 16, then X = 9. Fin
irakobra [83]

Answer:

Y = 441

Step-by-step explanation:

Given

M = 27 when Y = 16 and X = 9

Required

Find Y when M = 7 and X = 2

We start by getting the algebraic representation of the given statement

X^2 \alpha \frac{1}{\sqrt Y} \alpha M

Convert the variation to an equation; we have

X^2 = \frac{KM}{\sqrt Y}

<em>Where K is the constant of variation;</em>

When M = 27; Y = 16; X = 9, the expression becomes

9^2 = \frac{K * 27}{\sqrt{16}}

This gives

81 = \frac{k * 27}{4}

Make K the subject of formula

K = \frac{81* 4}{27}

K = \frac{324}{27}

K = 12

Solving for Y when M = 7 and X = 2

Recall that X^2 = \frac{KM}{\sqrt Y}

Substitute values for K, M and X

2^2 = \frac{12 * 7}{\sqrt{Y}}

4 = \frac{84}{\sqrt{Y}}

Take square of both sides

4^2 = (\frac{84}{\sqrt{Y}})^2

16 = \frac{7056}{Y}

Make  Y the subject of formula

Y = \frac{7056}{16}

Y = 441

3 0
3 years ago
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