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galina1969 [7]
3 years ago
6

There are 9 red markers, 5 blue markers. 14 yellow markers, and 8green markers in a pencil box. A marker is chosen at random, re

placed, then another is chosen. Find each probability. Answer in simplest fraction.
P( both yellow)


The answer is
Mathematics
1 answer:
viktelen [127]3 years ago
8 0

Answer:

Step-by-step explanation:

9+5+14+8= 36

yellow= 14/36

14   /    2   =   7

36   /     2  =   18

7/18

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Kruka [31]

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B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

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9!1! 1!2! 10! 3!

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= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
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5 0
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ipn [44]
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