What is the answer for (7-2)÷5

The height of a triangle is 8ft greater than the base. The area of the triangle is 136.5 square ft. Find the length of the base

mixer [17]

Answer:

the base is 9/2 ft and the height is 9/2 + 8, or 25/8, ft.

Step-by-step explanation:

Note that the formula for the area of a triangle is A = (1/2)(base)(height). Let's abbreviate that to A = (1/2)(b)(h). We are told that h = b + 8.

Then A = 136.5 = (1/2)(b)(b + 8), or

(after multiplying both sides by 2)

A = 273 = b^2 + 8b

which, when put into standard quadratic form, becomes:

b^2 + 8b - 273 = 0

The coefficients of this quadratic are a = 1, b = 8 and c = -273.

Thus, the discriminant is b^2 - 4ac, or 64 - 4(1)(-273) = 1156 = 17^2.

The roots are then

-8 ± √1156 -8 ± 17

x = -------------------- = ------------ = 9/2 and -25/2

2 2

Only the root 9/2 makes sense here, because measurements of length are positive.

Thus, the base is 9/2 ft and the height is 9/2 + 8, or 25/8, ft.

3 0

4 years ago

Marvin has a bag that contains 3 red marbles and 9 blue marbles he will randomly select a marble from the bag what is the probab

Anna71 [15]

Answer:

now how

Step-by-step explanation:

because he likes red marbles

i dont know

3 0

3 years ago

Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3

ehidna [41]

Algebraically prove that X^3+10/x^3+9=1+ 1/x^3+9 where x is not equal to -3
 $\dfrac{x^3+10}{x^3+9}=1+\dfrac{1}{x^3+9} \\ \\ \\ \dfrac{x^3+10}{x^3+9}=\dfrac{(x^3+9)+1}{x^3+9}\\ \\ \\ \dfrac{x^3+10}{x^3+9}=\dfrac{x^3+10}{x^3+9} \\ \\ \\x\in R \qquad x\in (-\infty, +\infty)$

7 0

4 years ago

Solve for x. 14+x>18 Enter your answer, as an inequality, in the box.

Andrej [43]

X is greater than or equal to 5

7 0

3 years ago

Do you hypotenuse of a triangle is 1 foot more than twice the length of the shorter leg the longer leg is 7 feet longer than the

Lera25 [3.4K]

Answer:

Shorter leg: 8 units

Longer leg: 15 units

Hypotenuse: 17 units

Step-by-step explanation:

We are given $h=1+2s$ where $h$ is the hypotenuse and $s$ is the length of the shorter leg.

We got this equation from reading that the "hypotenuse of a triangle is 1 foot more than twice the length of the shorter leg". I replaced the "hypotenuse of a triangle" with $h$ , "is" with $=$ , "1 foot more than" with $1+$ and finally "twice the length of the shorter leg" with $2s$ .

We also have "longer leg is 7 feet longer than the shorter leg".

I'm going to replace "longer leg" with $L$ .

I'm going to replace "is" with $=$ .

I'm going to replace "7 feet longer than the shorter leg" with $7+s$ .

So we have the equation $L=7+s$ .

So we have a right triangle since something there is a side being referred to as the hypotenuse. We can use Pythagorean Theorem to find a relation between all these sides.

So by Pythagorean Theorem, we have: $s^2+L^2=h^2$ .