Solve for ttt. 2(t+1) = 102(t+1)=10

Mathematics

2 answers:

densk [106]1 year ago

5 0

Answer:

2(t+1) = 102(t+1)=10

distribuite 2t+2=10

-8 2t=8

t=4

Ksju [112]1 year ago

3 0

Answer:

t=4

Step-by-step explanation:

you can pick which equation you want to do, i am picking the first one. 2(t+1)=10. first we simply the equation, we do this by multiplying the number outside of the parenthesis, 2, by t and 1. 2*t=2t, and 2*1 = 2, so he equation we have to solve is 2t+2=10. we can subtract 2 from the 2, and subtract 2 from the ten, so our equation is no 2t=8, 2* what equals 8, we know that 2*4=8, so t=4

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The distribution of IQ scores can be modeled by a normal distribution with mean 100 and standard deviation 15.

evablogger [386]

Answer:

4.4% of the population with IQ between 120 and 125.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.

a) Let X be a person's IQ score.

Then, density functions for IQ scores is given by:

$P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{z^2}{2}}\\\\\text{where,}\\\\z = \frac{x-\mu}{\sigma}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-100)^2}{450}}$

b) P(population with IQ between 120 and 125.)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

$P(120 \leq x \leq 125) = P(\displaystyle\frac{120 - 100}{15} \leq z \leq \displaystyle\frac{125-100}{15}) = P(1.33 \leq z \leq 1.66)\\\\= P(z \leq 1.66) - P(z < 1.33)\\= 0.952 - 0.908 = 0.044 = 4.4\%$