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2 years ago

Solve for ttt. 2(t+1) = 102(t+1)=10

Mathematics

2 answers:

densk [106]2 years ago

5 0

Answer:

2(t+1) = 102(t+1)=10

distribuite 2t+2=10

-8 2t=8

t=4

Ksju [112]2 years ago

3 0

Answer:

t=4

Step-by-step explanation:

you can pick which equation you want to do, i am picking the first one. 2(t+1)=10. first we simply the equation, we do this by multiplying the number outside of the parenthesis, 2, by t and 1. 2*t=2t, and 2*1 = 2, so he equation we have to solve is 2t+2=10. we can subtract 2 from the 2, and subtract 2 from the ten, so our equation is no 2t=8, 2* what equals 8, we know that 2*4=8, so t=4

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What is the 9th term of the geometric sequence 4, −20, 100, …?

sveta [45]

First, we are going to find the common ratio of our geometric sequence using the formula: $r= \frac{a_{n}}{a_{n-1}}$ . For our sequence, we can infer that $a_{n}=-20$ and $a_{n-1}=4$ . So lets replace those values in our formula:
$r= \frac{-20}{4}$
$r=-5$

Now that we have the common ratio, lets find the explicit formula of our sequence. To do that we are going to use the formula: $a_{n}=a_{1}*r^{n-1}$ . We know that $a_{1}=4$ ; we also know for our previous calculation that $r=-5$ . So lets replace those values in our formula:
$a_{n}=4*(-5)^{n-1}$

Finally, to find the 9th therm in our sequence, we just need to replace $n$ with 9 in our explicit formula:
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3 years ago

How to factorise? I need to factorise 4a^2 - 12b please show method

Lubov Fominskaja [6]

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so you just pull out the common factor between the two term 4
then you divide each term by the common factor to find what remain
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The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

Marina CMI [18]

<h2>Answer:</h2>

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

Origin.

<h2>Step-by-step explanation:</h2>

A function f(x) is said to be a odd function if:

$f(-x)=-f(x)$

Also, an odd function always has a symmetry with respect to the origin.

whereas a function f(x) is said to be a even function if:

$f(-x)=f(x)$

Also, an even function has a symmetry with respect to the y-axis.

We know that:

Tangent function, cotangent function and cosecant function are odd functions.

Since,

$\tan(-x)=-\tan x\\\\\cos (-x)=-\cot x\\\\\csc (-x)=-\csc x$

( similarly sine function is also an odd function.

whereas cosine and secant function are even functions )

<em>Hence, the graph of tangent function, cotangent function and cosecant function is symmetric about the origin.</em>

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Step-by-step explanation:

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Fynjy0 [20]

Answer:

Step-by-step explanation:

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